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svet-max [94.6K]
3 years ago
9

The lengths of text messages are normally distributed with a population standard deviation of 3 characters and an unknown popula

tion mean. If a random sample of 24 text messages i taken and results in a sample mean of 27 characters, find a 99% confidence interval for the population mean. Zo.10Z0.0520.025 Zo.01 Z0.005 1.282 1.645 1.960 2.326 2.576 You may use a calculator or the common z values above. Select the correct answer below: a.(26.21,27.79) b.(25.99.28.01) c.(25.93,28.07)
Mathematics
1 answer:
slava [35]3 years ago
5 0

Answer:

25.4, 28.6

Step-by-step explanation:

Given parameters

sample size, n = 24

sample mean, X = 27

population standard deviation, s = 3

critical value, Zα/2, where α = 0.01

99% confidence Interval, CI, is given as follows

CI = X ± Zα/2 × (s/√n)

Zα/2 = Z0.01/2 = Z0.005 = 2.576

CI = 27 ± 2.576 × (3/√24)

   = (25.42 ,28.57)

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sweet-ann [11.9K]

Answer:

{d,b}={4,3}

Step-by-step explanation:

[1]    11d + 17b = 95

  [2]    d + b = 7

Graphic Representation of the Equations :

   17b + 11d = 95        b + d = 7  

 

Solve by Substitution :

// Solve equation [2] for the variable  b

 [2]    b = -d + 7

// Plug this in for variable  b  in equation [1]

  [1]    11d + 17•(-d +7) = 95

  [1]    -6d = -24

// Solve equation [1] for the variable  d

  [1]    6d = 24

  [1]    d = 4

// By now we know this much :

   d = 4

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// Use the  d  value to solve for  b

   b = -(4)+7 = 3

Solution :

{d,b} = {4,3}

4 0
3 years ago
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Answer:

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Step-by-step explanation:

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So, 1\frac{?}{?}

Then, you would put 0.83 over a fraction.

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Answer:

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Step-by-step explanation:

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