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svet-max [94.6K]
3 years ago
9

The lengths of text messages are normally distributed with a population standard deviation of 3 characters and an unknown popula

tion mean. If a random sample of 24 text messages i taken and results in a sample mean of 27 characters, find a 99% confidence interval for the population mean. Zo.10Z0.0520.025 Zo.01 Z0.005 1.282 1.645 1.960 2.326 2.576 You may use a calculator or the common z values above. Select the correct answer below: a.(26.21,27.79) b.(25.99.28.01) c.(25.93,28.07)
Mathematics
1 answer:
slava [35]3 years ago
5 0

Answer:

25.4, 28.6

Step-by-step explanation:

Given parameters

sample size, n = 24

sample mean, X = 27

population standard deviation, s = 3

critical value, Zα/2, where α = 0.01

99% confidence Interval, CI, is given as follows

CI = X ± Zα/2 × (s/√n)

Zα/2 = Z0.01/2 = Z0.005 = 2.576

CI = 27 ± 2.576 × (3/√24)

   = (25.42 ,28.57)

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Explain weather 14t-3t is equivalent to 3t-14t. Support your sender by evaluating the expression for t=2.
m_a_m_a [10]

Answer:

Solving 14t-3t we get 22 and 3t-14t we get -22

So, 14t-3t is not equivalent to 3t-14t.

Step-by-step explanation:

We need to explain weather 14t-3t is equivalent to 3t-14t. Support your sender by evaluating the expression for t=2.

<em>Equivalent expressions are those that have same values for any value of variable substituted.</em>

Now, We check if our expressions are equivalent, by evaluating the expression for t=2.

If they are equivalent, they would have same result after evaluation.

First, put t=2 into 14t-3t

14t-3t\\Put\:t=2\\=14(2)-3(2)\\=28-6\\=22

Now put t=2, into 3t-14t

3t-14t\\Put\:t=2\\=3(2)-14(2)\\=6-28\\=-22\\

For solving 14t-3t we get 22 and 3t-14t we get -22

So, 14t-3t is not equivalent to 3t-14t.

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3 years ago
Test the claim that the proportion of men who own cats is smaller than 70% at the 0.05 significance level. The null and alternat
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Answer:

the null hypothesis would be: p = 70%/0.7

The alternative hypothesis would be: p < 0.7

Step-by-step explanation:

The null hypothesis is most of the time always the default statement while the alternative hypothesis is tested against the null and is its opposite.

In this case study the null hypothesis would be: the proportion of men who own cats is 70%: p = 0.7

The alternative hypothesis would be: the proportion of men who own cats is smaller than 70% : p < 0.7

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Answer:

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