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GenaCL600 [577]
3 years ago
10

5x−7=8 ; {1, 2, 3, 4} ? {hurry i will give you brainliest help}

Mathematics
1 answer:
Deffense [45]3 years ago
4 0

Answer:

x=3

Step-by-step explanation:

5x-7=8

add seven to both sides

5x=15

divide by 5

x=3

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Simplify the variable expression by evaluating it's numerical part m-13+42-6
goldfiish [28.3K]

ANSWER

m + 23

EXPLANATION

The given expression is

m - 13 + 42 - 6

We regroup the numerical parts to get;

m + 42 - 6 - 13

Now let us simplify the negative numbers.

m + 42 - 19

We now subtract 19 from 42 to get;

m + 23

We can't simplify further

Hence the simplest form is:

m + 23

3 0
4 years ago
150 miles in 6 gallons in unit rates
vazorg [7]

Answer:

1g/25m

Step-by-step explanation:

divide both of them by 6 so one of them can be one

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8 0
3 years ago
Suppose the heights of the members of a population follow a normal
valina [46]

Answer:

C; 62 to 68 inches

Step-by-step explanation:

Here, we want to get the population range that is having a probability of 68%

From the empirical rule, a measure of 1 standard deviation above the mean, with 1 standard deviation below the mean will give a total percentage of 68%

From the question;

1 standard deviation above the mean is 65 + 3 = 68

1 standard deviation below the mean is 65-3 = 62

so the range of the height of the population is 62 to 68 inches

5 0
3 years ago
92 - 16b = 12 help please
Reptile [31]

Answer:

b = -6.5

Step-by-step explanation:

92 - 16b = 12

now you want to get the number(s) and variables on different sides

92 - 16b - 92 = -16b

12 + 92 = 104

-16b = 104

now divide each side by -16

-16b / -16 = b

104 / -16 = -6.5

b = -6.5

8 0
4 years ago
The countries of Europe report that 46% of the labor force is female. The United Nations wonders if the percentage of females in
Anestetic [448]

Answer:

a) Point estimate p=0.43.

b) The 95% confidence interval for the population proportion of female workers in US is (0.388, 0.473).

c) This confidence interval tells us that, with 95% confidence, the true proportion of females in the U.S. labor force is within 0.388 and 0.473.

d) We can conclude that females do not make up a majority of the US labor force, because we can claim, with 95% confidence, that the true proportion of female workers is under 0.473, which is below 0.5 (or 50%).

Step-by-step explanation:

a) A point estimate can be calculated using the sample results and dividing the amount of female workers in the sample by the sample size:

p=X/n=226/525=0.43

b) We have to calculate a 95% confidence interval for the proportion.

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.43*0.57}{525}}\\\\\\ \sigma_p=\sqrt{0.000467}=0.022

The critical z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_p=1.96 \cdot 0.022=0.042

Then, the lower and upper bounds of the confidence interval are:

LL=p-z \cdot \sigma_p = 0.4305-0.042=0.388\\\\UL=p+z \cdot \sigma_p = 0.4305+0.042=0.473

The 95% confidence interval for the population proportion of female workers in US is (0.388, 0.473).

c) This confidence interval tells us that, with 95% confidence, the true proportion of females in the U.S. labor force is within 0.388 and 0.473.

d) We can conclude that females do not make up a majority of the US labor force, because we can claim, with 95% confidence, that the true proportion of female workers is under 0.473, which is below the 50%.

If the confidence interval have included the value 0.5, we could not be sure (with 95% confidence) that female workers do not represent de majority, as there would be possibility that the true proportion is 0.5.

3 0
4 years ago
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