I'm solving your system by substitution.
2x-4=5, 5x+4y =2
Step# 1: solve for x
2x - 4+ 4= 5 + 4( add +4 to both sides)
2x = 9
x = 9/2
Step# 2: solve for y
5(9/2) + 4y = 2
4y + 45/2 = 2
4y 45
y = 45/4 = 11.25
There is word form(which means write the number down, so lets just say I have the numbers 82,7,and 12. So I'll write eighty-two, seven, and twelve. There's also standard form, so lets say I have the numbers 27 and 15 I'll write 20+ 7, then 10+5.) I hope you got it! Good luck
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Answer: no
Step-by-step explanation:
( - 14x^3)(y^3) + 4x^5y^6)/(2x^4y^5)
= 4x^5y^6 - 14x^3y^3/2x^4y^5
= 4x^2y^3 - 14/2xy^2
= 2x^2y^3 - 7/xy^2
Answer: 2x^2y^3 - 7/xy^2
Hope that helps!!!!
1 3/10·b=39
(1·10+3)·b/10=39
13b/10=39
13b=39·10
13b=390|:13
<u>b=30</u>
<em>Answer: 30</em>
