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kipiarov [429]
3 years ago
10

in a factury that manufactures tires, a machine responsible for moking the tire has a failure rate of 0.2%. if 1,000 tired are p

roduced in a day, of which 6 are faulty, what is the difference between the experimental probability and the theoretical probability?
Mathematics
1 answer:
jenyasd209 [6]3 years ago
7 0
Theoretically you should get 2 faulty tires but experimentally you only got 6
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The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 270 day
dusya [7]

Answer:

a) 281 days.

b) 255 days

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 270, \sigma = 8

​(a) What is the minimum pregnancy length that can be in the top 8​% of pregnancy​ lengths?

100 - 8 = 92th percentile.

X when Z has a pvalue of 0.92. So X when Z = 1.405.

Z = \frac{X - \mu}{\sigma}

1.405 = \frac{X - 270}{8}

X - 270 = 1.405*8

X = 281

(b) What is the maximum pregnancy length that can be in the bottom 3​% of pregnancy​ lengths?

3rd percentile.

X when Z has a pvalue of 0.03. So X when Z = -1.88

Z = \frac{X - \mu}{\sigma}

-1.88 = \frac{X - 270}{8}

X - 270 = -1.88*8

X = 255

8 0
4 years ago
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