If 1.5 and 2.5 are the height and base, then just use Pythagorean theorem,
Answer:
![\huge\boxed{\sf SG = 31}](https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7B%5Csf%20SG%20%3D%2031%7D)
Step-by-step explanation:
<u>Given:</u>
SW = 3x + 1
WA = 6x
AG = x + 6
SW = AG
<u>Required:</u>
Length of SG = ?
<u>Solution:</u>
<u>Given that:</u>
SW = AG
3x + 1 = x + 6
Combining like terms
3x - x = 6 - 1
2x = 5
x = 5/2
x = 2.5
<u>Now,</u>
SG = SW + WA + AG
SG = 3x + 1 + 6x + x + 6
SG = 3x + 6x + x + 1 + 6
SG = 10x + 6
Put x = 2.5
SG = 10(2.5) + 6
SG = 25 + 6
SG = 31
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3><h3>Peace!</h3>
Answer:
6 *
larger
Step-by-step explanation:
divide
= 6 * ![10^{3}](https://tex.z-dn.net/?f=10%5E%7B3%7D)