2. How many 4-digit even numbers greater then 4,999 can be made(using the digits 0-9?

Mathematics

1 answer:

Lostsunrise [7]3 years ago

3 0

Answer:

For each choice of the first two digits you have 10 choices for the third digit. Thus you have 10x10x10 = 1000 choices for the first three digits. Finally you have 10 choices for the fourth digit and thus there are 10x10x10x10 = 10 000 possible 4 digit combinations from 0-9.

I hope that helps! :)

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