Answer:
technically, atoms have an infinite amount of levels of energy, but there are most likely 7 most known levels of atoms. All levels may contain electrons.
Explanation:
Answer: D.
Explanation:
For the supply to shift left, there must be a major development in the supply chain that will affect supply enough to decrease it for every price supplied.
Looking at the answers:
A. an increase in technology: this would not cause supply to be more expensive.
B. a decrease in the cost of a substitute would decrease demand, not supply.
C. an increase in consumer income levels would increase demand, as more consumers would be demanding more of the produce or service.
D. an increase in the cost of inputs for widgets would DECREASE supply, as the production of widgets is made more expensive at the same cost.
D is the correct answer.
The statement above is TRUE.
Social mobility refers to the movement of individuals or families within or between social strata in a particular society. It means a change in social status relative to one's present location with a given society. Social mobility in US does not depend on where one start in the class system; one can come from the lowest class strata and become one of the richest individual and an individual from a very rich family can also end up as a p.auper. A lot of factors come to play in these situations.
Answer:
E. systematic sample
Explanation:
Base on the scenario been described in the question, Paul Solomon the owner of Solly's, an upscale restaurant in Tampa, Florida, wants to know how good his advertising dollars is work, he hires Getty research to do this, Getty research advised to do a TOMA study, for Getty to draw it samples, they have to use systematic sampling.
Systematic sampling is a statistical method sampling that involves the selection of elements or members from a well ordered sampling frame.
Answer:
Part a: the magnitude of the volumetric heat generation rate is ![21.6 \times 10^6 W/m^3](https://tex.z-dn.net/?f=21.6%20%5Ctimes%2010%5E6%20W%2Fm%5E3)
Part b: the convective heat flux is
.
Part c: the amount of energy removed per unit area is ![1.2264 \times 10^7 J/m^2](https://tex.z-dn.net/?f=1.2264%20%5Ctimes%2010%5E7%20J%2Fm%5E2)
Explanation:
Part a
As per the heat equation
![\frac{d}{dx}(\frac{dT}{dx})+\frac{\dot{q}}{k}=0\\](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%28%5Cfrac%7BdT%7D%7Bdx%7D%29%2B%5Cfrac%7B%5Cdot%7Bq%7D%7D%7Bk%7D%3D0%5C%5C)
Here
T is given as
where x is in meters
k is given as 108 W/mK
So rearranging and solving for q' gives
![\dot{q}=-k\frac{d}{dx}(\frac{dT}{dx})\\\dot{q}=-108\frac{d}{dx}(\frac{d(300-0.1\times 10^4 x^2)}{dx})\dot{q}=-108\frac{d}{dx}(2\times (300-0.1\times 10^4 x))\\\dot{q}=-108\times 2\times (300-0.1\times 10^4 )\\\dot{q}=21.6 \times 10^6 W/m^3](https://tex.z-dn.net/?f=%5Cdot%7Bq%7D%3D-k%5Cfrac%7Bd%7D%7Bdx%7D%28%5Cfrac%7BdT%7D%7Bdx%7D%29%5C%5C%5Cdot%7Bq%7D%3D-108%5Cfrac%7Bd%7D%7Bdx%7D%28%5Cfrac%7Bd%28300-0.1%5Ctimes%2010%5E4%20x%5E2%29%7D%7Bdx%7D%29%5Cdot%7Bq%7D%3D-108%5Cfrac%7Bd%7D%7Bdx%7D%282%5Ctimes%20%28300-0.1%5Ctimes%2010%5E4%20x%29%29%5C%5C%5Cdot%7Bq%7D%3D-108%5Ctimes%202%5Ctimes%20%28300-0.1%5Ctimes%2010%5E4%20%29%5C%5C%5Cdot%7Bq%7D%3D21.6%20%5Ctimes%2010%5E6%20W%2Fm%5E3)
So the magnitude of the volumetric heat generation rate is ![21.6 \times 10^6 W/m^3](https://tex.z-dn.net/?f=21.6%20%5Ctimes%2010%5E6%20W%2Fm%5E3)
Part b
![q''_{conv}=h(T(L,0)-T_{\infty})](https://tex.z-dn.net/?f=q%27%27_%7Bconv%7D%3Dh%28T%28L%2C0%29-T_%7B%5Cinfty%7D%29)
Here
h is given as 1000W/m2K
T(L,0) is found by putting x=L in equation of T. L is given as 8cm=0.08m.
T_inf is the infinite temperature given as 20C or 293K.
So by substituting values in the equation.
![q''_{conv}=h(T(L,0)-T_{\infty})\\q''_{conv}=1000((300-0.1\times 10^4 (L^2)-293)\\q''_{conv}=1000((300-0.1\times 10^4 (0.08^2)-293)\\q''_{conv}=1000((300-0.1\times 10^4 (0.0064)-293)\\q''_{conv}=1000((300-6.4-293))\\q''_{conv}=600 W/m^2](https://tex.z-dn.net/?f=q%27%27_%7Bconv%7D%3Dh%28T%28L%2C0%29-T_%7B%5Cinfty%7D%29%5C%5Cq%27%27_%7Bconv%7D%3D1000%28%28300-0.1%5Ctimes%2010%5E4%20%28L%5E2%29-293%29%5C%5Cq%27%27_%7Bconv%7D%3D1000%28%28300-0.1%5Ctimes%2010%5E4%20%280.08%5E2%29-293%29%5C%5Cq%27%27_%7Bconv%7D%3D1000%28%28300-0.1%5Ctimes%2010%5E4%20%280.0064%29-293%29%5C%5Cq%27%27_%7Bconv%7D%3D1000%28%28300-6.4-293%29%29%5C%5Cq%27%27_%7Bconv%7D%3D600%20W%2Fm%5E2)
So the convective heat flux is
.
Part c:
For energy balance
![\dot{E_{in}}-\dot{E_{out}}=\dot{E_{st}}](https://tex.z-dn.net/?f=%5Cdot%7BE_%7Bin%7D%7D-%5Cdot%7BE_%7Bout%7D%7D%3D%5Cdot%7BE_%7Bst%7D%7D)
Here as
is zero
So
![-\dot{E_{out}}=\dot{E_{st}}](https://tex.z-dn.net/?f=-%5Cdot%7BE_%7Bout%7D%7D%3D%5Cdot%7BE_%7Bst%7D%7D)
It is given as
![-\dot{E_{out}}=\dot{E_{st}}=\rho c_p(T_{final}-T_{\infty})-\rho c_p\int\limits^{x=L}_{x=0} ({T_{x,0}-T_{\infty}) \, dx](https://tex.z-dn.net/?f=-%5Cdot%7BE_%7Bout%7D%7D%3D%5Cdot%7BE_%7Bst%7D%7D%3D%5Crho%20c_p%28T_%7Bfinal%7D-T_%7B%5Cinfty%7D%29-%5Crho%20c_p%5Cint%5Climits%5E%7Bx%3DL%7D_%7Bx%3D0%7D%20%28%7BT_%7Bx%2C0%7D-T_%7B%5Cinfty%7D%29%20%5C%2C%20dx)
Here as T_final and T_inf will be same so
Also ρ is given as 7000 kg/m3
cp=450 J/kg.K
![\dot{E_{out}}=\rho c_p\int\limits^{x=L}_{x=0} {(T_{x,0}-T_{\infty}) \, dx}\\\dot{E_{out}}=7000 \times 450\int\limits^{x=L}_{x=0} {(300-0.1\times 10^4 x^2-293) \, dx}\\\dot{E_{out}}=3150000[300x-0.1\times 10^4 \frac{x^3}{3}-293x]_0^L\\\dot{E_{out}}=3150000[300(0.08)-0.1\times 10^4 \frac{(0.08)^3}{3}-293(0.08)]\\\dot{E_{out}}=3150000(0.3893)\\\dot{E_{out}}=1.2264 \times 10^7 J/m^2](https://tex.z-dn.net/?f=%5Cdot%7BE_%7Bout%7D%7D%3D%5Crho%20c_p%5Cint%5Climits%5E%7Bx%3DL%7D_%7Bx%3D0%7D%20%7B%28T_%7Bx%2C0%7D-T_%7B%5Cinfty%7D%29%20%5C%2C%20dx%7D%5C%5C%5Cdot%7BE_%7Bout%7D%7D%3D7000%20%5Ctimes%20450%5Cint%5Climits%5E%7Bx%3DL%7D_%7Bx%3D0%7D%20%7B%28300-0.1%5Ctimes%2010%5E4%20x%5E2-293%29%20%5C%2C%20dx%7D%5C%5C%5Cdot%7BE_%7Bout%7D%7D%3D3150000%5B300x-0.1%5Ctimes%2010%5E4%20%5Cfrac%7Bx%5E3%7D%7B3%7D-293x%5D_0%5EL%5C%5C%5Cdot%7BE_%7Bout%7D%7D%3D3150000%5B300%280.08%29-0.1%5Ctimes%2010%5E4%20%5Cfrac%7B%280.08%29%5E3%7D%7B3%7D-293%280.08%29%5D%5C%5C%5Cdot%7BE_%7Bout%7D%7D%3D3150000%280.3893%29%5C%5C%5Cdot%7BE_%7Bout%7D%7D%3D1.2264%20%5Ctimes%2010%5E7%20J%2Fm%5E2)
So the amount of energy removed per unit area is ![1.2264 \times 10^7 J/m^2](https://tex.z-dn.net/?f=1.2264%20%5Ctimes%2010%5E7%20J%2Fm%5E2)