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STALIN [3.7K]
3 years ago
5

Use the Venn diagram to calculate probabilities.

Mathematics
1 answer:
Rudiy273 years ago
8 0

<u>Corrected Question</u>

These are the given probabilities. The Venn diagram is also attached. are (A) P(A|C) = 2/3

(B) P(C|B) = 8/27

(C) P(A) = 31/59

(D) P(C) = 3/7

(E) P(B|A) = 13/27

Answer:

A and C

Step-by-step explanation:

P(A|C)=\dfrac{P(A\cap C)}{P(C)}= \dfrac{14/59}{21/59}=\dfrac{14}{21}=\dfrac{2}{3}

P(C|B) =\dfrac{P(C\cap B)}{P(B)}= \dfrac{11/59}{27/59}=\dfrac{11}{27}\neq \dfrac{8}{27}\\\\P(A) = \dfrac{31}{59}\\\\P(C) =\dfrac{21}{59}\neq \dfrac{3}{7}\\\\P(B|A)=\dfrac{P(B\cap A)}{P(A)}= \dfrac{13/59}{31/59}=\dfrac{13}{31}\neq\dfrac{13}{27}

From the above, only A and C are correct.

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Let us say

The Height from which the ball was first dropped as H0 = 248 feet

The Height reached by the ball after second bounce is H1

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Given , Height the ball reaches after bounce is a fraction of the height the ball reached in the previous bounce

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