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ad-work [718]
3 years ago
6

bridget has swimming lessons every fifth day and diving lessons every third day. If she had a swimming lesson and a diving lesso

n on May 5, when will be the next date on which she has both swimming and diving lessons?
Mathematics
2 answers:
lara [203]3 years ago
8 0
She had both on May 5

swimming lessons every 5th day
5,10,15,20

diving lessons every 3rd day...
3,6,9,12,15

so they both have a common multiple of 15

so fifteen days after May 5 = May 20 <==
d1i1m1o1n [39]3 years ago
5 0

Answer:

On May 20,

Step-by-step explanation:

In order to calculate on which date both her lessons will fall on the same date, we take the LCM of 3 and 5.

Factors of 3 ⇒ 1 × 3

Factors of 5 ⇒ 1 × 5

Since 1 is common, we take it once and multiply with other non-common factors.

Therefore LCM = 1 × 3 × 5 = 15

Thus after 15 days of 5th may = 20th May

she has both lessons on May 20 after May 5.

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Which statement describes the inverse of m(x) = x^2 – 17x?
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Given:

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m(x)=x^2-17x

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The inverse of the given function.

Solution:

We have,

m(x)=x^2-17x

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y=x^2-17x

Interchange x and y.

x=y^2-17y

Add square of half of coefficient of y , i.e., \left(\dfrac{-17}{2}\right)^2 on both sides,

x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2

x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2

x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2        [\because (a-b)^2=a^2-2ab+b^2]

Taking square root on both sides.

\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}

Add \dfrac{17}{2} on both sides.

\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y

Substitute y=m^{-1}(x).

m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}

We know that, negative term inside the root is not real number. So,

x+\left(\dfrac{17}{2}\right)^2\geq 0

x\geq -\left(\dfrac{17}{2}\right)^2

Therefore, the restricted domain is x\geq -\left(\dfrac{17}{2}\right)^2 and the inverse function is m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}.

Hence, option D is correct.

Note: In all the options square of \dfrac{17}{2} is missing in restricted domain.

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