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ad-work [718]
3 years ago
6

bridget has swimming lessons every fifth day and diving lessons every third day. If she had a swimming lesson and a diving lesso

n on May 5, when will be the next date on which she has both swimming and diving lessons?
Mathematics
2 answers:
lara [203]3 years ago
8 0
She had both on May 5

swimming lessons every 5th day
5,10,15,20

diving lessons every 3rd day...
3,6,9,12,15

so they both have a common multiple of 15

so fifteen days after May 5 = May 20 <==
d1i1m1o1n [39]3 years ago
5 0

Answer:

On May 20,

Step-by-step explanation:

In order to calculate on which date both her lessons will fall on the same date, we take the LCM of 3 and 5.

Factors of 3 ⇒ 1 × 3

Factors of 5 ⇒ 1 × 5

Since 1 is common, we take it once and multiply with other non-common factors.

Therefore LCM = 1 × 3 × 5 = 15

Thus after 15 days of 5th may = 20th May

she has both lessons on May 20 after May 5.

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yes

Step-by-step explanation:

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3 years ago
3/x+1 -1/2 = 1/3x+3 please help solve
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\frac{3}{x+1}^{(6}-\frac{1}{2}^{(3x+3}=\frac{1}{3x+3}^{(2} \\\\ 18-3x-3=2 \\\\ -3x+15=2\\\\ -3x=2-15 \\\\-3x=-13 \\\\ \boxed{x=\frac{13}{3}}
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3 years ago
Problem 10-01 NPV A project has an initial cost of $66,950, expected net cash inflows of $14,000 per year for 9 years, and a cos
svlad2 [7]

Answer:

NPV = $13,676.33

Step-by-step explanation:

First, find the present value of the cash inflows. You can solve this question using a Financial calculator;

14,000 per year is a recurring cashflow hence the PMT

PMT = 14,000

I/Y = 10%

N= 9

FV =0

then CPT PV = 80,626.33

NPV = -Initial investment + PV of future cash inflows

NPV = -66,950 + 80,626.33

NPV = $13,676.33

"NPV" button, then , then "CPT".

The answer to the NPV = $13,676.33

5 0
3 years ago
I REALLY NEED HELP!!!!!!!
Reil [10]
Do you think the answer is C.147?
3 0
3 years ago
In a right triangle, one leg is 20 cm and the hypotenuse is 30 cm. To the nearest hundredth of a cm, find the length of the miss
max2010maxim [7]

Answer:

Step-by-step explanation:

Use Pythagoras’ theorem

square of hypotenuse = sum of squares of two other sides

let the missing side be d

30^2 = 20^2 + d^2

600 = 400 + d^2

d^2 = 200

d = square root of 200

d = 14.142 cm

3 0
3 years ago
Read 2 more answers
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