Answer:
x=1
Step-by-step explanation:
According to your typed question,
f(x)=2x-3
Let f(x)=y
y=2x-3
Now,
Interchanging the positions of x and y
x=2y-3
x+3=2y
x+3/2=y
f'(x)=x+3/2
Then,
f(x)=f'(x)
2x-3=x+3/2
2(2x-3)=x+3
4x-3=x+3
4x-x=3+3
3x=3
x=3/3
x=1
According to your image question,
f(x)=x/2x-3
f(x)=f'(x)
Now,
Let y=f(x)
y=x/2x-3
y(2x-3)=x
2xy-3=x
2xy-x=3
x(2y-1)=3
2y-1=3x
2y=3x+1
y=3x+1/2
f'(x)=3x+1/2
Then,
f(x)=f'(x)
x/2x-3=3x+1/2
2x=6xsq+2x-9x+3
2x=6xsq+7x+3
solve for x ok
Hello,
i would go for A)
take it as a guess
Answer=15:39
Step1(find the number of right handed batters)
Left-handed batters=45
5 45
__=___
8 x
Cross multiply
5x=360
divide both sides by 5
x=72
Right-handed batters=72
Step 2 (find the number of total batters)
total batters=45+72=117
Step3 (find the ratio of left handed batters to total batters)
Left-handed batters to total batters= 45/117
45/117 can be shortened to 15/39
Answer=15:39
