Radius AM is perpendicular to line R. True False

Does anyone know the answer to this (:

Alecsey [184]

Answer:

A. triangle 4 and triangle 3.

Step-by-step explanation:

If you look at triangle 4, you can see that it need to be rotated and reflected.

If you look at triangle 3, you can see that it needs to be reflected.

4 0

4 years ago

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Helppp plzz I will give brainlist

ra1l [238]

#1. look at the individual probability first.
A dice has 6 sides. The numbers > 2 are {3, 4, 5, 6}. So the chance of rolling a number > 2 is 4/6 or 2/3 simplified.
Multiples of 3 on a dice are {3, 6}. So the chance of rolling a multiple of 3 is 2/6 or 1/3 simplified.

Rolling a dice is an independent event, like flipping a coin the previous roll does not have an effect on the outcome of the next roll. So when you see the word AND connecting the outcomes, you multiply them.

Prob of rolling >2 AND then multiple of 3 = (2/3)*(1/3)
= 2/9

#2. The total socks in the drawer: 8+8+4= 20 socks
The probability of first drawing a blue sock is 8/20 or 2/5 simplified.

Since the question does not say the socks are put back in the drawer, the total number of socks and number of blue socks decrease by 1 after the first draw. This makes the next draw dependent on the first.
The probability of drawing a blue sock is then: 7/19
because there's a blue sock missing.

Probability of drawing blue sock AND then a blue sock (without replacement)
= (2/5)*(7/19)
= 14/95

8 0

4 years ago

How do you solve 3 times 2/4

Leya [2.2K]

Answer:

1 1/2 or 1.5

Step-by-step explanation:

6 0

4 years ago

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Does anyone know the answer? 19 points if u answer + brainliest answer! :P

kakasveta [241]

Answer:

first start by finding the equation and then put it into photomath and then boom theres your answer hun

Step-by-step explanation:

6 0

3 years ago

41. Assuming that a man can complete the work alone in x days, his work in four days would be: a) b) X X C d) 4x x 42. If a man

Schach [20]

Percentage and ratio word problems require understanding of the relationship between variables from which the question is formed

The options that give the correct values of the duration of the work are;

$41. \ c) \ \dfrac{4}{x}$

$42. \ d) \ \dfrac{4}{x} + \dfrac{6}{y} = \dfrac{1}{5}$

43. a) 35 days

44. c) 21·a + 28·b = 1

45. c) (42, 56)

Reasons:

41. Number of days it takes a man to complete the work alone = x days

Therefore;

$The \ work \ done \ by \ the \ man \ in \ one \ day = \dfrac{1}{x}$

$The \ work \ done \ in \ four \ days \ by\ the \ man = 4 \times \dfrac{1}{x} = \dfrac{4}{x}$

The correct option is $c) \ \dfrac{4}{x}$

42. Number of days it takes a man to complete the work alone = x days

$Work \ done \ by \ a\ man \ in \ one \ day = \dfrac{1}{x}$

$Work \ done \ by \ four \ men \ in \ one \ day = \dfrac{4}{x}$

Number of days it takes a boy to complete the work alone = y days

$Work \ done \ by \ a \ boy \ in \ one \ day = \dfrac{1}{x}$

$Work \ done \ by \ six \ boys \ in \ one \ day = \dfrac{6}{y}$

4 men and 6 boys work for 5 days to complete the work

Therefore, work done by 4 men and 6 boys in 1 day is therefore;

$\dfrac{4}{x} + \dfrac{6}{y} = \dfrac{1}{5}$

The correct option is therefore;

$d) \ \dfrac{4}{x} + \dfrac{6}{y} = \dfrac{1}{5}$

43. As per the case study, we have;

Case 1

$\dfrac{4}{x} + \dfrac{6}{y} = \dfrac{1}{5}$

Which gives;

$\dfrac{6\cdot x + 4\cdot y}{y \cdot x} = \dfrac{1}{5}$

30·x + 20·y = y·x

Case 2

$\dfrac{3}{x} + \dfrac{4}{y} = \dfrac{1}{7}$

Which gives;

$\dfrac{4\cdot x + 3\cdot y}{y \cdot x} = \dfrac{1}{7}$

28·x + 21·y = y·x

Therefore;

30·x + 20·y = 28·x + 21·y

∴ 2·x = y

Plugging in the value of y = 2·x, in Case 1 gives;

$\dfrac{4}{x} + \dfrac{6}{2 \cdot x} = \dfrac{1}{5}$

$\dfrac{2 \times 4 + 6}{2 \times x} = \dfrac{14}{2 \times x} =\dfrac{7}{x} = \dfrac{1}{5}$

7 × 5 = x

x = 7 × 5 = 35

The number of days, x, it takes a man to complete the work alone, is given by option; a) 35 days

44. For the equation $\dfrac{3}{x} + \dfrac{4}{y} = \dfrac{1}{7}$ , if $a = \dfrac{1}{x}$ , and $b = \dfrac{1}{y}$ , we have;

$3 \cdot a+ 4\cdot y = \dfrac{1}{7}$

21·a + 28·y = 1

The correct option is option C. 21·a + 28·b = 1

45. A solution to the equation $\dfrac{3}{x} + \dfrac{4}{y} = \dfrac{1}{7}$ , is given by the values of x, and y, that gives;

$\dfrac{1}{14} + \dfrac{1}{14} = \dfrac{1}{7}$

We have;

3 × 14 = 42

4 × 14 = 56

Therefore, a solution to the equation is (42, 56)

The correct option is $c) \ \underline{ (42, \ 56)}$

Learn more here:

brainly.com/question/11825953

brainly.com/question/14626596

brainly.com/question/15573651

3 0

2 years ago