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antiseptic1488 [7]
4 years ago
9

A baker has 5 1/4 pies in her shop. She cut the pies in pieces that are each 1/8 of a whole pie.

Mathematics
1 answer:
aivan3 [116]4 years ago
7 0

Answer:

42 pieces of pie


Step-by-step explanation:


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Anyone ??<br> I’m confused
Ad libitum [116K]
+2+(-3)+(-1)+4(-5)+(-3) ok so first 2 is positive and 3 is negative there both different signs so u subtract +2+(-3)=-1+(-1)=0+4=4+(-5)=-1+(-3)=-4 your answer is 4
4 0
3 years ago
Crystal estimated that repairs to her car would cost about $100. The cost of repairs was actually $175. Fill in the box with Cry
Feliz [49]

percent error=100 times error/predicted

error=175-100=75

predicted=100

percent error=100 times 75/100=75

the answer si 75% error

7 0
4 years ago
If A(−1, 1), B(−4, 5), C(−9, 5), and D(−6, 1) are the vertices of a quadrilateral, do the points form a rhombus? Justify your an
Flura [38]

Answer:

Yes, it is a rhombus because the slope of diagonal segment BD equals 2, the slope of diagonal segment AC equals -1/2, and the diagonals bisect each other.

Step-by-step explanation:

The slope of diagonal BD is ...

  slope BD = (change in y)/(change in x) = (-4/-2) = 2

The slope of diagonal AC is ...

  slope AC = (change in y)/(change in x) = (4/-8) = -1/2

The midpoint of BD is ...

  ((-4, 5) +(-6, 1))/2 = (-10, 6)/2 = (-5, 3)

The midpoint of AC is ...

  ((-1, 1) +(-9, 5))/2 = (-10, 6)/2 = (-5, 3)

so the diagonals bisect each other.

While the third statement is true (both midpoints are the same), that fact alone is not sufficient to allow the figure to be declared a rhombus. The diagonals must also be perpendicular (have slopes whose product is -1). The appropriate answer choice is the <em>second one</em>:

  • Yes, it is a rhombus because the slope of diagonal segment BD equals 2, the slope of diagonal segment AC equals -1/2, and the diagonals bisect each other.
3 0
3 years ago
Which equation is NOT equivalent to p – 7 = 22? Select all that apply.<br> please help
Ghella [55]
Options C, D, E. You should be able to simplify each one and realise that CDE does not equal the given equation
8 0
4 years ago
When the expression $-2x^2-20x-53$ is written in the form $a(x+d)^2+e$, where $a$, $d$, and $e$ are constants, then what is the
Sladkaya [172]
We start with 2 x^{2} -20x-53 and wish to write it as a(x+d) ^{2} +e

First, pull 2 out from the first two terms: 2( x^{2} -10x)-53

Let’s look at what is in parenthesis. In the final form this needs to be a perfect square. Right now we have x^{2} -10x and we can obtain -10x by adding -5x and -5x. That is, we can build the following perfect square: x^{2} -10x+25=(x-5) ^{2}

The “problem” with what we just did is that we added to what was given. Let’s put the expression together. We have 2( x-5) ^{2}-53 and when we multiply that out it does not give us what we started with. It gives us 2 x^{2} -20x+50-53=2 x^{2} -20x-3

So you see our expression is not right. It should have a -53 but instead has a -3. So to correct it we need to subtract another 50.

We do this as follows: 2(x-5) ^{2}-53-50 which gives us the final expression we seek:

2(x-5) ^{2}-103

If you multiply this out you will get the exact expression we were given. This means that:
a = 2
d = -5
e =  -103

We are asked for the sum of a, d and e which is 2 + (-5) + (-103) = -106


7 0
3 years ago
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