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antiseptic1488 [7]
3 years ago
9

A baker has 5 1/4 pies in her shop. She cut the pies in pieces that are each 1/8 of a whole pie.

Mathematics
1 answer:
aivan3 [116]3 years ago
7 0

Answer:

42 pieces of pie


Step-by-step explanation:


You might be interested in
The circumference of a standard baseball is about 9in. About how many square inches of horsehide are required to cover 100 balls
Marta_Voda [28]
This is the concept of area of solid materials, we are required to calculate the total area of horsehide that is required to cover 100 balls with each having a circumference of 9 in.
The area of hide required will be given by:
area=(area of each ball)*(total number of balls)
area of each ball is given by:
SA=4πr^2
given that the circumference is 9in, we are required to find the radius of the ball
Circumference, c=2πr
thus;
9=2πr
r=9/(2π)
r=1.4 in
Therefore the surface area will be:
SA=4π*1.4^2=24.6 in^2
Therefore the area of horsehide required to cover 100 balls will be:
Area=24.6*100=2,460 in^2.
5 0
3 years ago
6(y + 7) = 2(y - 3)<br> What is the answer ?
andrew11 [14]

Answer:

Y= -12

Step-by-step explanation:

6(y + 7) = 2(y - 3)

6y+42=2y-6

4y+42=-6

4y=-48

y=-12

7 0
3 years ago
Tangent line i think please help me find x
Alex

Answer:

x= 6.5 cm

Step-by-step explanation:

When a tangent line touches the circle, it forms a right angle triangle at that point

Apply the Pythagorean relationship in this case

Given that the height is = 20.2 cm = b

The hypotenuse is = c= x+14.7 cm

General formulae is;

a² +b² =c²

x² + 20.2² =( x+ 14.7)²

x² + 408.04= x² +14.7x+14.7x+216.09

x² + 408.04= x² + 29.4 x +216.09.........................collect like terms

x²-x² + 408.04-216.09= 29.4x

191.95= 29.4x-------------------------------divide by 29.4 t0 get x

191.95/29.4 =x

x=6.5 cm

6 0
3 years ago
Question 2
choli [55]
%6 of the sixth graders are left handed
8 0
3 years ago
What number is 10^2 times as long as 0.012?
Strike441 [17]
100, 3/250 because 10x10 is 100 and 0.012 converted into fraction is 3/250
7 0
3 years ago
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