3^20 = 3,486,784,401. How many other whole numbers can you raise to a power

Mathematics

1 answer:

deff fn [24]3 years ago

5 0

Two more whole numbers 9 and 81

Step-by-step explanation:

$3^{20} = 3,486,784,401 \\ \\ ( {3}^{2} )^{10} = 3,486,784,401 \\ \\ \huge \red{ \boxed{{9}^{10} = 3,486,784,401}} \\ \\ ( {9}^{2} )^{5} = 3,486,784,401 \\ \\ \huge \red{ \boxed{{81}^{5} = 3,486,784,401 }}\\ \\$

So, two more whole numbers 9 and 81 can be raised to a power to get 3,486,784, 401.

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All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$