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Sphinxa [80]
3 years ago
6

Ms. Walker's science class is doing an egg drop experiment from the balcony of their school. Each egg is protected by a contrapt

ion that the students collectively designed. The height of the egg, in feet, after x seconds is given by the expression below. What do the zeros of the expression represent? A. the maximum height of the egg B. the time at which the egg reaches its maximum height C. the horizontal distance traveled by the egg D. the time at which the egg reaches the ground
Mathematics
1 answer:
zepelin [54]3 years ago
7 0

Answer:

An object balances itself when a perpendicular line drawn through its Centre of Gravity (CG), passes through its base.

See the picture of a popular toy given below. The horse, the rider and the ball are all joined together as one single unit. This entire unit is balanced on the thin black rod shown. At which of the indicated positions, could the Centre of Gravity (CG) of the horse, rider and ball unit be?

July 10 book Science up55 down8

AA BB

CC DD

Step-by-step explanation:

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What is the area of this triangle?
Lana71 [14]

Remember

A=1/2 b x h



4 0
3 years ago
Choose the true statement. -2 < -3 -2 > -3 -2 = -3Choose the true statement.
Marrrta [24]
-2 < -3 (I think so anyway)
7 0
3 years ago
Law of radicals
andrey2020 [161]

Answer:

1)  \sqrt{x^7}=x^{\frac{7}{2}

2)  \sqrt[3]{y^5}=y^{\frac{5}{3}

3) \sqrt[5]{a^{12}}=a^{\frac{12}{5} }

4) \sqrt[4]{z^{9}}=z^\frac{9}{4}

Step-by-step explanation:

1) \sqrt{x^7}

We know that \sqrt{x}=x^{\frac{1}{2}

So, \sqrt{x^7}=x^{\frac{7}{2}

2) \sqrt[3]{y^5}

We know that \sqrt[3]{x}=x^{\frac{1}{3}

So, \sqrt[3]{y^5}=y^{\frac{5}{3}

3) \sqrt[5]{a^{12}}

We know that \sqrt[5]{x}=x^{\frac{1}{5}

So, \sqrt[5]{a^{12}}=a^{\frac{12}{5} }

4) \sqrt[4]{z^{9}}

We know that \sqrt[4]{x}=x^{\frac{1}{4}

So, \sqrt[4]{z^{9}}=z^\frac{9}{4}

6 0
3 years ago
A farmer plowed a rectangular section of land for a new crop. The section measures 24 1/2 yd by 38 1/2 yd. Find the total area i
MAVERICK [17]

Answer: 943\dfrac{1}{4}\text{ sq. yds}

Step-by-step explanation:

Given ,  A farmer plowed a rectangular section of land for a new crop.

Dimensions of the section is given by :-

Length by width = 24\dfrac{1}{2}\text{ yd by }38\dfrac{1}{2}\text{ yd}

Since , the area of a rectangle = length x width

Then, the total area in yards of plowed section of land will be:

24\dfrac{1}{2}\times38\dfrac{1}{2}\text{ sq. yds}\\\\=\dfrac{2(24)+1}{2}\times\dfrac{2(38)+1}{2}\text{ sq. yds}\\\\=\dfrac{49}{2}\times\dfrac{77}{2}\text{ sq. yds}\\\\=\dfrac{3773}{4}\text{ sq. yds}\\\\=943\dfrac{1}{4}\text{ sq. yds}

Hence, the total area in yards of plowed section of land =  943\dfrac{1}{4}\text{ sq. yds}

8 0
3 years ago
0.7(3x−0.2)=0.3(0.8−2x)<br><br> URGENT<br><br> 20 Points!<br><br> Please Help!!!
topjm [15]

Answer:

x = .140741

Step-by-step explanation:

0.7(3x−0.2)=0.3(0.8−2x)

Distribute

.7 * 3x - .7*.2 = .3*.8 - .3 * 2x

2.1x - .14 = .24 - .6x

Add .6x to each side

2.1x +.6x -.14 = .24 -.6x+.6x

2.7x -.14 = .24

Add .14 to each side

2.7x -.14+.14 = .24+.14

2.7x = .38

Divide by 2.7 on each side

2.7x/2.7 = .38/2.7

x = .140741

3 0
3 years ago
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