The picture is very blurry I can’t see , wish I could help doe !!! Can you still mark brainliest for effort of trying to help !?
We know that
If the scalar product of two vectors<span> is zero, both vectors are </span><span>orthogonal
</span><span>A. (-2,5)
</span>(-2,5)*(1,5)-------> -2*1+5*5=23-----------> <span>are not orthogonal
</span><span>B. (10,-2)
</span>(10,-2)*(1,5)-------> 10*1-2*5=0-----------> are orthogonal
<span>C. (-1,-5)
</span>(-1,-5)*(1,5)-------> -1*1-5*5=-26-----------> are not orthogonal
<span>D. (-5,1)
</span>(-5,1)*(1,5)-------> -5*1+1*5=0-----------> are orthogonal
the answer is
B. (10,-2) and D. (-5,1) are orthogonal to (1,5)
Answer:
2. n = 11
4. g = -2
6. t = 21
8. n = 4
10. y = -1
Step-by-step explanation:
2. 63 = -3(1 - 2n)
Dividing both the side by negative 3 we get

4. -g + 2(3 + g) = -4(g + 1)
First we will open the bracket by distributive property A( B +C) = AB + AC

6.-3(t +5 ) + (4t + 2) = 8
Using distributive property A( B +C) = AB + AC we get

8. -8 - n = -3(2n -4)
Using distributive property A( B +C) = AB + AC we get

10. -4( 2 - y) + 3y = 3(y - 4)
Using distributive property A( B +C) = AB + AC we get

Answer:
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Step-by-step explanation: