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3 years ago

Distance between (-3,5) an (-4,1)

Mathematics

1 answer:

forsale [732]3 years ago

3 0

Answer:

Step-by-step explanation:

note : distance between A(X1,Y1) an B (X2,Y2) is :

AB= √((X2 - X1)² + (Y2 - Y1)²)

in this exercice : X1 = -3 X2 = - 4 Y1 = 5 Y2 = 1

continue .....calculate AB

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A company has 8 mechanics and 6 electricians. If an employee is selected at random, what is the probability that they are an ele

Andre45 [30]

Answer:

$Probability = \frac{3}{7}$

Step-by-step explanation:

Given

Electrician = 6

Mechanic = 8

Required

Determine the probability of selecting an electrician

First, we need the total number of employees;

$Total = n(Electrician) + n(Mechanic)$

$Total = 6 + 8$

$Total = 14$

Next, is to determine the required probability using the following formula;

$Probability = \frac{n(Electrician)}{Total}$

$Probability = \frac{6}{14}$

Divide numerator and denominator by 2

$Probability = \frac{3}{7}$

Hence, the probability of selecting an electrician is 3/7

4 0

3 years ago

Suppose that a large pumpkin empty a swimming pool in 40 hours and that a small pumpkin empty a pool and 70 hours working togeth

Norma-Jean [14]

Answer:

Total 25.45 hours will be taken to empty the pool.

Step-by-step explanation:

Time taken by large pumpkin to empty the pool=40 hours

Time taken by the smaller pumpkins to empty the pool=70 hours

Amount of pool emptied by large pumpkin in one hour= $\frac{1}{40}$

Amount of pool emptied by small pumpkin in one hour= $\frac{1}{70}$

Amount of pool emptied in one hour if both pumpkins work together=

$\frac{1}{40}$ + $\frac{1}{70}$

= $\frac{11}{280}$

Therefore, the no. of days will be the reciprocal of the amount of work done in one hour ie . $\frac{280}{11}$

Total 25.45 hours will be taken to empty the pool.

5 0

3 years ago

Hi please help me.. will give brainlest

chubhunter [2.5K]

Answer:

Volume = l*w*h

Equation: 1620 = 9*9*h

1620=81h

h=20 cm

4 0

2 years ago

Read 2 more answers

A jet’s speed in still air is 240 mph. One day it flew 700 miles with a tailwind (the wind pushing it along) and then returned t

Bess [88]

Speed of the wind for jet speed in still air 240mph and jet covers 700 miles with tailwind and same distance against the wind in total time of 6 hours is equal to 40mph.

As given in the question,

Given data:

Jet speed in still air = 240mph

Let x be the speed of the wind.

Speed with tail wind = 240 +x

Distance covered with tail wind = 700miles

Time taken by jet with tail wind

= Distance/ speed

= 700 / (240 +x) __(1)

Speed against the wind = 240 - x

Distance covered against the wind = 700miles

Time taken by jet against the wind

= Distance/ speed

= 700 / (240 - x) __(2)

Total time taken is 6 hours

[700 / (240 +x)] + [700 / (240 - x)] = 6

⇒ 700( 240 -x + 240 + x) = 6 (240 +x)(240 - x)

⇒ 700 ( 480) = 6 ( 240² -x²)

⇒ 700 (80) = 57600 -x²

⇒ x² = 57600 - 56000

⇒ x² = 1600

⇒ x = √1600

⇒ x= 40 mph

Therefore, speed of the wind for jet speed in still air 240mph and jet covers 700 miles with tailwind and same distance against the wind in total time of 6 hours is equal to 40mph.

Learn more about speed here

brainly.com/question/28224010

#SPJ1

6 0

10 months ago

Find F(-2) F(x)=5^x A=1/25 B=1/10 C=-10 D=-25

kati45 [8]

F(-2) when F(x)=5^x is 1/25

7 0

3 years ago