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grigory [225]
3 years ago
9

Please help me this is hard for me

Mathematics
1 answer:
adell [148]3 years ago
8 0

Answer:

i think its c

Step-by-step explanation:

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The questions are in the images pls answer all or your answer will be deleted because this is for a lot of points and im losing
PilotLPTM [1.2K]

1)

x + 2y = 21

+ -x + 3y = 29

--------------------------

5y = 50

y = 10

x + 2(10) =21

x = 1

2)

6x + 6y = 30

+ 15x - 6y = 12

-------------------------------

21x = 42

x = 2

6(2) + 6y = 30

6y = 18

y = 3

7 0
3 years ago
Which graph shows the axis of symmetry for the function f(x) = (x – 2)2 + 1? On a coordinate plane, a vertical dashed line at (n
Deffense [45]

The axis of symmetry of f(x) is:

On a coordinate plane, a vertical dashed line at (2, 0) is parallel to

the y-axis ⇒ 2nd answer

Step-by-step explanation:

The vertex form of a quadratic function is f(x) = a(x - h)² + k, where

  • (h , k) are the coordinates of its vertex point
  • The axis of symmetry of it is a vertical line passes through (h , 0)
  • The minimum value of the function is y = k at x = h

∵ f(x) = a(x - h)² + k

∵ f(x) = (x - 2)² + 1

∴ a = 1 , h = 2 , k = 1

∵ The axis of symmetry of f(x) is a vertical line passes through (h , 0)

∴ The axis of symmetry of f(x) is a vertical line passes through (2 , 0)

∵ Any vertical line is parallel to y-axis

∴ The axis of symmetry of f(x) is a vertical line parallel to y-axis and

   passes through (2 , 0)

The axis of symmetry of f(x) is:

On a coordinate plane, a vertical dashed line at (2, 0) is parallel to

the y-axis

   

Learn more:

You can learn more about quadratic function in brainly.com/question/9390381

#LearnwithBrainly

6 0
3 years ago
Read 2 more answers
A technician is launching fireworks near the event of a show. Of the remaining 11 fireworks, 4 are blue and 7 are red. If she la
SpyIntel [72]

\displaystyle |\Omega|=\binom{11}{6}=\dfrac{11!}{6!5!}=\dfrac{7\cdot8\cdot9\cdot10\cdot11}{2\cdot3\cdot4\cdot5}=462\\ |A|=\binom{4}{2}=\dfrac{4!}{2!2!}=\dfrac{3\cdot4}{2}=6\\\\ P(A)=\dfrac{6}{462}=\dfrac{1}{77}\approx1\%

8 0
3 years ago
If the slope of PQ is 2/3 and the slope of QR is-1/2 , find the slope of SR so that PQRS is a parallelogram.
schepotkina [342]
SR is parallel to PQ so has the same slope as PQ, which is 2/3
6 0
3 years ago
Write an equation in point-slope form of the line that passes through (-4,1) and (4,3).
Step2247 [10]

Answer:

An equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

y-1=\frac{1}{4}\left(x+4\right)

Step-by-step explanation:

Given the points

  • (-4,1)
  • (4,3)

Finding the slope between the points (-4,1) and (4,3)

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-4,\:1\right),\:\left(x_2,\:y_2\right)=\left(4,\:3\right)

m=\frac{3-1}{4-\left(-4\right)}

Refine

m=\frac{1}{4}

Point slope form:

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

in our case,

  • m = 1/4
  • (x₁, y₁) = (-4,1)

substituting the values m = 1/4 and the point (-4,1) in the point slope form of line equation.

y-y_1=m\left(x-x_1\right)

y-1=\frac{1}{4}\left(x-\left(-4\right)\right)

y-1=\frac{1}{4}\left(x+4\right)

Thus, an equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

y-1=\frac{1}{4}\left(x+4\right)

5 0
2 years ago
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