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rusak2 [61]
3 years ago
9

In a school of 464 students, 89 students are in band, 215 are on sports teams, and 31 participate in both activites. How many st

udents are involded in neither band nor sports?
Mathematics
1 answer:
Tema [17]3 years ago
5 0

Answer:

The answer to your question is 191

Step-by-step explanation:

Data

Total number of students = 464

Students in a band = 89

Students in sports = 215

Students in both activities = 31

Students do not practice any activity = ?

Process

1.- Subtract 31 from the students in a band and students in a sport

        89 - 31 = 58

       215 - 31 = 184

2.- Add the previous results anfd the number of students that practice both activities

         58 + 184 + 31 = 273

3.- Subtract 273 from the total number of students

         464 - 273 = 191

4.- Conclusion

191 students are not involved in any activity.

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Step-by-step explanation:

20x2= 40

40÷8= 5

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Hoochie [10]

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3 years ago
184500 $ are to be divided between 2 people. One person has 80% of what the other person has. How much does each one receive in
Annette [7]

Given:

$184500 are to be divided between 2 people.

One person has 80% of what the other person has.

To find:

The amount each one receive in $.

Solution:

Let $x be the amount received by first person. Then,

Amount received by the second person = 80% of x

                                                                   = 0.80x

Total amount = Amount received by first person + by second person

                      =x+0.80x

                      =1.80x

Total amount is 184500. So,

1.80x=184500

x=\dfrac{184500}{1.80}

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So, the amount received by the first person is $102,500.

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3 years ago
CAN SOMEONE PLEASE PLEASE PLEASE HELP ME, YOU’LL GET FREE EASY POINTS IF YOU GIVE ME THE RIGHT ANSWER !!
bekas [8.4K]

Answer:

  1. reflection across BC
  2. the image of a vertex will coincide with its corresponding vertex
  3. SSS: AB≅GB, AC≅GC, BC≅BC.

Step-by-step explanation:

We want to identify a rigid transformation that maps congruent triangles to one-another, to explain the coincidence of corresponding parts, and to identify the theorems that show congruence.

__

<h3>1.</h3>

Triangles GBC and ABC share side BC. Whatever rigid transformation we use will leave segment BC invariant. Translation and rotation do not do that. The only possible transformation that will leave BC invariant is <em>reflection across line BC</em>.

__

<h3>2.</h3>

In part 3, we show ∆GBC ≅ ∆ABC. That means vertices A and G are corresponding vertices. When we map the congruent figures onto each other, <em>corresponding parts are coincident</em>. That is, vertex G' (the image of vertex G) will coincide with vertex A.

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<h3>3.</h3>

The markings on the figure show the corresponding parts to be ...

  • side AB and side GB
  • side AC and side GC
  • angle ABC and angle GBC
  • angle BAC and angle BGC

And the reflexive property of congruence tells us BC corresponds to itself:

  • side BC and side BC

There are four available congruence theorems applicable to triangles that are not right triangles

  • SSS -- three pairs of corresponding sides
  • SAS -- two corresponding sides and the angle between
  • ASA -- two corresponding angles and the side between
  • AAS -- two corresponding angles and the side not between

We don't know which of these are in your notes, but we do know that all of them can be used. AAS can be used with two different sides. SAS can be used with two different angles.

SSS

  Corresponding sides are listed above. Here, we list them again:

  AB and GB; AC and GC; BC and BC

SAS

  One use is with AB, BC, and angle ABC corresponding to GB, BC, and angle GBC.

  Another use is with BA, AC, and angle BAC corresponding to BG, GC, and angle BGC.

ASA

  Angles CAB and CBA, side AB corresponding to angles CGB and CBG, side GB.

AAS

  One use is with angles CBA and CAB, side CB corresponding to angles CBG and CGB, side CB.

  Another use is with angles CBA and CAB, side CA corresponding to angles CBG and CGB, side CG.

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