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ivolga24 [154]
3 years ago
11

The Great Pyramid at Giza has a square base with sides of length 230 meters and a height of 146.7 meters. Approximately what is

the volume of the Great Pyramid?
Mathematics
1 answer:
marissa [1.9K]3 years ago
8 0

Answer:

2586810 m³

Step-by-step explanation:

To find the volume of a pyramid, we find the area of the base multiplied by the height, then mulitplied by 1/3:

V = 1/3Bh

Since the base is a square, the area of this is found by the side length squared, making our formula

V = 1/3s²h

V = 1/3(230)²(146.7)

V = 1/3(52900)(146.7)

V = 1/3(7760430)

V = 2586810

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5÷3.5=1.4
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2 years ago
Which points are on the perpendicular bisector of the given segment? Check all that apply. Please explain how you got your answe
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First, you have to find the equation of the perpendicular bisector of this given line. 
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the slope of the perpendicular line is the negative reciprocal of the slope of the given line, m=-3/1=-3 
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4 0
2 years ago
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4 0
3 years ago
What are the solution(s) to the quadratic equation 50 – x2 = 0?
Dmitrij [34]

Answer:

x = ±5\sqrt{2}

Step-by-step explanation:

We have been given the quadratic equation;

50-x^{2}=0

The first step is to subtract 50 from both sides of the equation;

50-x^{2}-50=0-50

-x^{2}=-50

Multiplying both sides by -1 yields;

x^{2}=50

The final step is to obtain square roots on both sides;

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Therefore, x = ±5\sqrt{2}

5 0
3 years ago
Systems of equations and inequalities<br> solving systems by elimination<br> {y= -x+1<br> {y= 4x-14
kodGreya [7K]

Answer:

x = 3  , y = -2

Step-by-step explanation:

Solve the following system:

{y = 1 - x | (equation 1)

y = 4 x - 14 | (equation 2)

Express the system in standard form:

{x + y = 1 | (equation 1)

-(4 x) + y = -14 | (equation 2)

Swap equation 1 with equation 2:

{-(4 x) + y = -14 | (equation 1)

x + y = 1 | (equation 2)

Add 1/4 × (equation 1) to equation 2:

{-(4 x) + y = -14 | (equation 1)

0 x+(5 y)/4 = (-5)/2 | (equation 2)

Multiply equation 2 by 4/5:

{-(4 x) + y = -14 | (equation 1)

0 x+y = -2 | (equation 2)

Subtract equation 2 from equation 1:

{-(4 x)+0 y = -12 | (equation 1)

0 x+y = -2 | (equation 2)

Divide equation 1 by -4:

{x+0 y = 3 | (equation 1)

0 x+y = -2 | (equation 2)

Collect results:

Answer: {x = 3  , y = -2

5 0
3 years ago
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