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olga2289 [7]
3 years ago
10

Each salt shaker holds 1 1/4

Mathematics
2 answers:
MrRa [10]3 years ago
7 0

Answer: It will fill 8 salt shakers.

Step-by-step explanation:

Ivahew [28]3 years ago
4 0

Answer:

8 Shakers

Step-by-step explanation:

Divide 10 by 1 1/4

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Answer:

A and C the other two are just stand alone numbers. so the answers are A and C

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The figure shows a kite inside a rectangle. Which expression represents the area of the shaded region? 2x2 4x2 6x2 8x2
notka56 [123]
The picture in the attached figure

we know that
area of the <span>the shaded region=area of rectangle -area of a kite

area of rectangle=(3x+x)*(x+x)----> 4x*2x---> 8x</span>²

area of a kite=(1/2)*[d1*d2]
where d1 and d2 are the diagonals
d1=4x
d2=2x
so
area of a kite=(1/2)*[4x*2x]----> 4x²

area of the the shaded region=8x²-4x²-----> 4x²

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4x²

5 0
3 years ago
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The students in Mr. Sanchez's class are converting distances measured in miles to kilometers. To estimate the number of kilomete
BaLLatris [955]

Step-by-step explanation:

Abby’s Expression:

Double m, giving 2m. She then takes 20% of the result, which we can write 0.2(2m). Finally she subtracts this from 2m, giving 2m−(0.2)2m

2m − (0.2)2m

Renato’s Expression:

Divide m by 5, giving m ÷ 5 = m/5, and then multiplies the result by 8, giving:

8(m/5)

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4 0
3 years ago
A car has mass 1500 kg and is traveling at a speed of 35 miles/hour. what is its kinetic energy in joules? (Be sure to convert m
photoshop1234 [79]

Answer:

Factor by which kinetic energy increase = 4 times

Step-by-step explanation:

Given,

  • Mass of the car, v1 = 1500 kg
  • initial speed of car = 35 miles/h

                               =\dfrac{35\times 1609.34}{3600}\ m/s

                               = 15.64 m/s

Initial kinetic energy of the car is given by,

k_1\ =\ \dfrac{1}{2}.m.v_1^2

       =\ \dfrac{1}{2}\times 1500\times (15.64)^2\ joule

       = 183606.46 J

  • Final velocity of car v2 = 70 miles/hour

                                      =\dfrac{70\times 1609.34}{3600}

                                      = 31.29 m/s

So, final kinetic energy of car is given by

k_2\ =\ \dfrac{1}{2}.m.v_2^2

        =\ \dfrac{1}{2}\times 1500\times (31.29)^2

        = 734425.84 J

Now, the ratio of final to initial kinetic energy can be given by,

\dfrac{k_2}{k_1}=\ \dfrac{734425.84}{183606.46}

=>\ k_2\ =\ 4k_1                      

Hence, the kinetic energy will increase by 4 times.

7 0
3 years ago
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