Answer:
a range of values such that the probability is C % that a rndomly selected data value is in that range
Step-by-step explanation:
complete question is:
Select the proper interpretation of a confidence interval for a mean at a confidence level of C % .
a range of values produced by a method such that C % of confidence intervals produced the same way contain the sample mean
a range of values such that the probability is C % that a randomly selected data value is in that range
a range of values that contains C % of the sample data in a very large number of samples of the same size
a range of values constructed using a procedure that will develop a range that contains the population mean C % of the time
a range of values such that the probability is C % that the population mean is in that range
Hello there.
To answer this question, we need to remember some properties about the vertex of quadratic functions.
Let
. Its vertex can be found on the coordinates
such that
and
, in which
.
Using the coefficients given by the question, we get that:
![x_v=-\dfrac{8}{2\cdot(-1)}\\\\\\ x_v=-\dfrac{8}{-2}\\\\\\ x_v=4](https://tex.z-dn.net/?f=x_v%3D-%5Cdfrac%7B8%7D%7B2%5Ccdot%28-1%29%7D%5C%5C%5C%5C%5C%5C%20x_v%3D-%5Cdfrac%7B8%7D%7B-2%7D%5C%5C%5C%5C%5C%5C%20x_v%3D4)
Thus, we have:
![y=f(x_v)=f(4)](https://tex.z-dn.net/?f=y%3Df%28x_v%29%3Df%284%29)
So the statement is true, because the
coordinate of the vertex of the function is equal to ![4.~~\checkmark](https://tex.z-dn.net/?f=4.~~%5Ccheckmark)
Answer:
-5/2
Step-by-step explanation:
to find the slope of the line, you have to do y1 - y2, over x1 - x2. That means that you do -5/2, and so that is the answer