3 years ago

Read all of the statements about scale drawings below.

Mathematics

1 answer:

Sever21 [200]3 years ago

7 0

Answer:

The first and second statements are true

Step-by-step explanation:

Scale drawings are easier to work with than the actual object because they help a person understand the measurement better because they have scales

They should have the same proportion as the actual object in order to help calculate the real measurement of the object using the scale ratio

HOPE IT HELPED

You might be interested in

PLEASE HELP! 50 POINTS!!!!! Which expression(s) are equivalent to -2x + 10

galina1969 [7]

The answer is b hope that helps

7 0

2 years ago

If ZMK APY, m M = 112 ° , m Y = 41 ° , m K = (13x 37) ° , and m A = (2y + 7) ° , find the values of x and y.

Lunna [17]

Answer

13x-37=112

13x =149

X=11.4

2y+7=41

Y=24

5 0

2 years ago

Read 2 more answers

Pls I need help now pls help me

VARVARA [1.3K]

1. yes

2. yes

3. no

4. yes

5. yes

7 0

2 years ago

Read 2 more answers

Prove that H c G is a normal subgroup if and only if every left coset is a right coset, i.e., aH = Ha for all a e G

Kaylis [27]

$\Rightarrow$

Suppose first that $H\subset G$ is a normal subgroup. Then by definition we must have for all $a\in H$ , $xax^{-1} \in H$ for every $x\in G$ . Let $a\in G$ and choose $(ab)\in aH$ ( $b\in H$ ). By hypothesis we have $aba^{-1} =abbb^{-1}a^{-1}=(ab)b(ab)^{-1} \in H$ , i.e. $aba^{-1}=c$ for some $c\in H$ , thus $ab=ca \in Ha$ . So we have $aH\subset Ha$ . You can prove $Ha\subset aH$ in the same way.

$\Leftarrow$

Suppose $aH=Ha$ for all $a\in G$ . Let $h\in H$ , we have to prove $aha^{-1} \in H$ for every $a\in G$ . So, let $a\in G$ . We have that $ha^{-1} =a^{-1}h'$ for some $h'\in H$ (by the hypothesis). hence we have $aha^{-1}=h' \in H$ . Because $a$ was chosen arbitrarily we have the desired .

5 0

3 years ago

the area of a room in a dollhouse is 1248 square inches. the width of the room is 8 inches. how long is the room

zaharov [31]

The dollhouse is 156 inches long.

Area is computed by multiplying the length to its width.

A = L * W

Use the formula and substitute the values given in the problem.
A = 1248 sq. inches
w = 8 inches
L = ?

1248 = L * 8

L = 1248 sq. in/ 8 in
L = 156 inches

7 0

2 years ago

Read 2 more answers