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AURORKA [14]
2 years ago
13

Read all of the statements about scale drawings below.

Mathematics
1 answer:
Sever21 [200]2 years ago
7 0

Answer:

The first and second statements are true

Step-by-step explanation:

Scale drawings are easier to work with than the actual object because they help a person understand the measurement better because they have scales

They should have the same proportion as the actual object in order to help calculate the real measurement of the object using the scale ratio

HOPE IT HELPED

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PLEASE HELP! 50 POINTS!!!!! Which expression(s) are equivalent to -2x + 10
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The answer is b hope that helps
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If ZMK APY, m M = 112 ° , m Y = 41 ° , m K = (13x 37) ° , and m A = (2y + 7) ° , find the values of x and y.
Lunna [17]

Answer

13x-37=112

13x =149

X=11.4

2y+7=41

Y=24

5 0
2 years ago
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VARVARA [1.3K]

1. yes

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Prove that H c G is a normal subgroup if and only if every left coset is a right coset, i.e., aH = Ha for all a e G
Kaylis [27]

\Rightarrow

Suppose first that H\subset G is a normal subgroup. Then by definition we must have for all a\in H, xax^{-1} \in H for every x\in G. Let a\in G and choose (ab)\in aH (b\in H). By hypothesis we have aba^{-1} =abbb^{-1}a^{-1}=(ab)b(ab)^{-1} \in H, i.e. aba^{-1}=c for some c\in H, thus ab=ca \in Ha. So we have aH\subset Ha. You can prove Ha\subset aH in the same way.

\Leftarrow

Suppose aH=Ha for all a\in G. Let h\in H, we have to prove  aha^{-1} \in H for every a\in G. So, let a\in G. We have that ha^{-1} =a^{-1}h' for some h'\in H (by the hypothesis). hence we have aha^{-1}=h' \in H. Because a was chosen arbitrarily  we have the desired .

 

5 0
2 years ago
the area of a room in a dollhouse is 1248 square inches. the width of the room is 8 inches. how long is the room
zaharov [31]
The dollhouse is 156 inches long.

Area is computed by multiplying the length to its width.

A = L * W

Use the formula and substitute the values given in the problem.
A = 1248 sq. inches
w = 8 inches
L = ?

1248 = L * 8

L = 1248 sq. in/ 8 in
L = 156 inches
7 0
2 years ago
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