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Bezzdna [24]
3 years ago
5

(SAT Prep) How many distinct triangles are for which the lengths of the sides are 5,9 and n, where n is an integer and 10

Mathematics
2 answers:
Nana76 [90]3 years ago
7 0
The answer is C because you can have a triangle with 5,9,n   5,10,n   9,10,n   and 5,10,9

The reason why is because the sum of two sides is always larger than the value of the third side.

I hope that this helps.

Arada [10]3 years ago
7 0

Answer:

it's b

Step-by-step explanation:

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I would say you cannot use a rectangle. Or a circle. One of those.
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As part of a science experiment, Sam recorded the four values shown in the table, but one of them got smudged on his paper. He r
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Answer:

C

Step-by-step explanation:

ok so sam started with 0 and got -9 then he got 12 then the next known number is -8 so those three numbers together are -5 and the end result was -1 so -1 minus -5 is -4 therefore the anser is C

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Here is a question for you
dimaraw [331]

Answer:

3/8

Step-by-step explanation:

they simply combined the like terms (aka the x numbers in this case) so all that's left is 3/8

6 0
3 years ago
6x-4y=-14 <br>-3x-3y=12<br><br>with the elimination method
Vanyuwa [196]
6x-4y=-14
2(-3x-3y=12)

6x-4y=-14
-6x-6y=24

-10y=10
Divide both sides by 10
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y=-1

6x-4(-1)=-14
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8 0
3 years ago
Tina was asked to determine the possible dimensions of a given rectangle whose area is 12a4b3-18a6b3-72a7b3. Tina stated that th
Rufina [12.5K]

Answer:

Tina is correct

Step-by-step explanation:

Given

Area = 12a^4b^3 - 18a^6b^3 - 72a^7b^3

Required

State if 3a^4b^3(4-6a^2-24a^3) is a possible dimension

To do this, we simply expand 3a^4b^3(4-6a^2-24a^3)

3a^4b^3(4-6a^2-24a^3)

3a^4b^3 * 4-3a^4b^3 * 6a^2-3a^4b^3 * 24a^3

12a^4b^3 - 18a^{4+2}b^3 * -72a^{4+3}b^3

12a^4b^3 - 18a^{6}b^3 * -72a^{7}b^3

By comparison, the result of the expansion

12a^4b^3 - 18a^{6}b^3 * -72a^{7}b^3

and the given expression

Area = 12a^4b^3 - 18a^6b^3 - 72a^7b^3

are the same.

<em>Hence, Tina is correct</em>

7 0
2 years ago
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