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3 years ago

BRAINLIEST!!PLEASE HELP

Mathematics

1 answer:

zimovet [89]3 years ago

4 0

D the 2 represents the two sets of length and width pairs

2(l + w) = 2l + 2w , that is 2 times length + 2 times width

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I would like to have equal fish tanks for my fish. I have 12 angel fish and 24 sword fish and 30 guppies .How many tanks will I

velikii [3]

I would find the common factors between all of them, and settle with the factor 3.

If I have 3 tanks:

12/3 = 4

24/3 = 8

30/3 = 10

In each of the 3 tanks, there will be 4 angel fish, 8 sword fish, and 10 guppies.

I hope I helped :)

(I hope I didn't misunderstand the question, so if I did, I'm really sorry about that.)

7 0

3 years ago

Which expression is equivalent to

pychu [463]

Answer:

Step-by-step explanation:

i cannot find an answer from the expression but i can guess if you didnt follow pemdas, it would be d

3.5 × 102 is 357

(8 × 10−4) + (6 × 10−4) is 132

132/357= .369 or .37 or 0 simplified

d is 4*10-10

10-10 is 0

4*0 is 0

8 0

3 years ago

How many fluid ounces are in 3 quarts and 2 cups ?

sasho [114]

15 fluid ounces.
1quart= 4 cups

8 0

4 years ago

Read 2 more answers

Suppose $1000 is invested at a rate of 13% per year compounded monthly. (Round your answers to the nearest cent.)

masya89 [10]

Answer:

a. $1010.83

b.$1066.77

c. $1138.00

d.$13,269.22

Step-by-step explanation:

Given the annual rate as 13%(compounded monthly) and the principal amount as $1000.

a. #first we calculate the effective annual rate;

$i_m=(1+i/m)^m-1\\\\i_{12}=(1+0.13/12)^{12}-1=0.1380$

The compounded amount after 1 month is therefore:

$P_1=P(1+I_m)^n, n=1/12, i_m=0.1380, P=1000\\\\P_1=1000(1+0.1380)^{1/12}\\\\P_1=1010.83$

Hence, the principle after one month is $1010.83

b. The principal after 6 months:

-From a above we have the effective annual rate as 0.1380 and our time is 6 months:

$P_{6m}=P(1+i_m)^n, \ n=6m, P=1000, i_m=0.1380\\\\P_{6m}=1000(1+0.1380)^{6/12}\\\\=1066.77$

Hence, the principal after 6 months is $1066.77

c.The principal after 1 year:

-From a above we have the effective annual rate as 0.1380 and our time is 12 months:

$P_{1y}=P(1+I_m)^n, n=1/12, i_m=0.1380, P=1000\\\\P_{1y}=1000(1+0.1380)^{12}\\\\P_{1y}=1138$

Hence, the principal after 1 year is $1138.00

d. The principal after 20years:

-From a above we have the effective annual rate as 0.1380 and our time is 20yrs:

$P_{20y}=P(1+I_m)^n, n=1/12, i_m=0.1380, P=1000\\\\P_{20y}=1000(1+0.1380)^{12}\\\\P_{20y}=13269.22$

Hence, the principal after 20 years is $13,269.22

3 0

4 years ago

Evaluate the expression using order of operations 8-3[{4+2}+6]=?

DENIUS [597]

8- 3[{4+2}+6]
= 8 - 3[6+6]
= 8 - 3 (12)
= 8 - 36
= -28

3 0

4 years ago