The sequence
diverges.
For given question,
We have been given a sequence 
We need to determine whether the sequence converges or diverges.
From given sequence we have, 
We use Ratio Test.
According to Ratio Test,
, where sequence converges if and only if |r| < 1.
Consider,
![\lim_{n \to \infty} |\frac{a_{n+1}}{a_n} |\\\\= \lim_{n \to \infty} |\frac{\frac{(n+1)^2}{(n+1)^3+5(n+1)}}{\frac{n^2}{n^3+5n}} |\\\\\\= \lim_{n \to \infty} |\frac{(n+1)^2(n^3+5n)}{n^2[(n+1)^3+5(n+1)]} |\\\\=\infty](https://tex.z-dn.net/?f=%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20%7C%5Cfrac%7Ba_%7Bn%2B1%7D%7D%7Ba_n%7D%20%7C%5C%5C%5C%5C%3D%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20%7C%5Cfrac%7B%5Cfrac%7B%28n%2B1%29%5E2%7D%7B%28n%2B1%29%5E3%2B5%28n%2B1%29%7D%7D%7B%5Cfrac%7Bn%5E2%7D%7Bn%5E3%2B5n%7D%7D%20%7C%5C%5C%5C%5C%5C%5C%3D%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20%7C%5Cfrac%7B%28n%2B1%29%5E2%28n%5E3%2B5n%29%7D%7Bn%5E2%5B%28n%2B1%29%5E3%2B5%28n%2B1%29%5D%7D%20%7C%5C%5C%5C%5C%3D%5Cinfty)
Since
is not defined, the sequence
diverges.
Therefore, the sequence
diverges.
Learn more about the sequence here:
brainly.com/question/17175513
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Answer:
8 years
Step-by-step explanation:
Lets write an equation for Type A
The initial value is 5 ft and the slope 12 inches
We need to have the same units, so lets change 5 ft to inches
5 ft * 12 inches / ft = 60 inches
y = mx+b
y = 12 x + 60
Lets write an equation for Type B
The initial value is 3 ft and the slope 15 inches
We need to have the same units, so lets change 3 ft to inches
3 ft * 12 inches / ft = 36 inches
y = mx+b
y = 15 x + 36
We want to know when y is the same value. We can set the equations equal.
12x + 60 = 15x+36
Subtract 12 x from each side
12x-12x+60 = 15x-12x +36
60 =3x+36
Subtract 36 from each side
60-36 = 3x+36-36
24 = 3x
Divide each side by 3
24/3 = 3x/3
8 =x
It will take 8 years for the trees to be the same height
Answer:
S is not the subspace of 
Step-by-step explanation:
Let us suppose two vectors u and v belong to the S such that the property of xy≥0 is verified than
![v=\left[\begin{array}{c}0 \\1\end{array}\right]](https://tex.z-dn.net/?f=v%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D0%20%5C%5C1%5Cend%7Barray%7D%5Cright%5D)
Both the vectors satisfy the given condition as follows and belong to the S

Now S will be termed as subspace of R2 if
- u+v also satisfy the condition
- ku also satisfy the condition
Taking u+v
![u+v=\left[\begin{array}{c}-1 \\0\end{array}\right]+\left[\begin{array}{c}0 \\1\end{array}\right]\\u+v=\left[\begin{array}{c}-1+0 \\0+1\end{array}\right]\\u+v=\left[\begin{array}{c}-1 \\1\end{array}\right]](https://tex.z-dn.net/?f=u%2Bv%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D-1%20%5C%5C0%5Cend%7Barray%7D%5Cright%5D%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D0%20%5C%5C1%5Cend%7Barray%7D%5Cright%5D%5C%5Cu%2Bv%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D-1%2B0%20%5C%5C0%2B1%5Cend%7Barray%7D%5Cright%5D%5C%5Cu%2Bv%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D-1%20%5C%5C1%5Cend%7Barray%7D%5Cright%5D)
Now the condition is tested as

This indicates that the condition is not satisfied so S is not the subspace of 
<h2><u>
Answer with explanation:</u></h2>
Let
be the population mean strain in a way that conveys information about precision and reliability.
The sample mean is the best point estimate of the true population mean .
As per given , we have
Sample size : n= 12
degree of freedom : 
Sample mean : 
The true average strain in a way that conveys information about precision and reliability= 25.0
sample standard deviation : s= 3.3
Significance level : 
Since sample population standard deviation is unknown , so we use t-test.
Critical t-value for t : 
95% Confidence interval for true average strain in a way that conveys information about precision and reliability:


The 95% Confidence interval for true average strain in a way that conveys information about precision and reliability: 
We 95% confident that the true population average strain in a way that conveys information about precision and reliability lies between 22.9 and 27.1 .
Answer:
4x^2
Step-by-step explanation:
Call the unknown side y
The area of the figure is
8x^3 *y = 32 x^5
Divide each side by 8 x^3
8x^3 *y / 8x^3 = 32 x^5 / 8x^3
y = 4 x^2
The unknown side is 4 x^2