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inn [45]
3 years ago
5

Exercise #4: Kirk has 12 dollars less than Jim. If Jim spends half of his money, and Kirk spends none, then

Mathematics
1 answer:
Alinara [238K]3 years ago
3 0

Answer: Jim had $28 , Kirk had $16

Step-by-step explanation:

Let's represent the amount of money they had initially as k and j respectively.

From the first statement, Kirk has 12 dollars less than Jim. Mathematically, this could be expressed as :

K + 12 = J or K = J - 12

From the second sentence, we can deduce the following : If Jim's initial amount is halved, Kirk would be 2 dollars richer. This could he expressed mathematically as ;

J/2 = K - 2

NOW , let's solve both equations simultaneously.

K = J - 12 ..........(i)

J/2 = K - 2 ........(ii)

Let's substitute for k in equation ii using equation I

J/2 = J - 12 - 2

J/2 = J - 14

J = 2J - 28

Rearranging yields

2J - J = 28

J = 28

Since K = J - 12, that means k = 28 - 12 = 16

Hence initially, Jim had $28 while Kirk had $16

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1. I am a three-digit number. My tens digit is 3 more than my
Tems11 [23]

Answer:

1. 474

2. 397

Step-by-step explanation:

1. If the three-digit number is xyz, then y = z + 3.

When rounded to the nearest ten and reduced by 320, the result is 150.  150 + 320 = 470, so x = 4.  y = 6 if z ≥ 5, and y = 7 if z < 5.

So the number is either 463 or 474.  463 doesn't round to 470, so the answer is 474.

2. If the three-digit number is xyz, then z = x + 4.  y is the largest of the three digits; since all the digits are odd, y is either 5, 7, or 9.  So z is either 5 or 7, and x is either 1 or 3.

When rounded to the nearest hundred and reduced by 100, the result is 300.  100 + 300 = 400, and y > 5, so xyz is rounded up to 400, which means x = 3.  So z = 7 and y = 9.

The answer is 397.

6 0
3 years ago
This is a math question if you are good this is good for you this is hard
lubasha [3.4K]

Answer:

Hope this helps!

Step-by-step explanation:

1- -24

2- -23

3- -2

4- 11

5- 5

6- -3

7- 28

8- 120

7 0
3 years ago
Refer to the following scenario:You want to see if there is a difference between the exercise habits of Science majors and Math
bekas [8.4K]

Answer:

1. H0: P1 = P2

2. Ha: P1 ≠ P2

3. pooled proportion p = 0.542

4. P-value = 0.0171

5. The null hypothesis failed to be rejected.

At a signficance level of 0.01, there is not enough evidence to support the claim that there is significant difference between the exercise habits of Science majors and Math majors .

6. The 99% confidence interval for the difference between proportions is (-0.012, 0.335).

Step-by-step explanation:

We should perform a hypothesis test on the difference of proportions.

As we want to test if there is significant difference, the hypothesis are:

Null hypothesis: there is no significant difference between the proportions (p1-p2 = 0).

Alternative hypothesis: there is significant difference between the proportions (p1-p2 ≠ 0).

The sample 1 (science), of size n1=135 has a proportion of p1=0.607.

p_1=X_1/n_1=82/135=0.607

The sample 2 (math), of size n2=92 has a proportion of p2=0.446.

p_2=X_2/n_2=41/92=0.446

The difference between proportions is (p1-p2)=0.162.

p_d=p_1-p_2=0.607-0.446=0.162

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{82+41}{135+92}=\dfrac{123}{227}=0.542

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.542*0.458}{135}+\dfrac{0.542*0.458}{92}}\\\\\\s_{p1-p2}=\sqrt{0.001839+0.002698}=\sqrt{0.004537}=0.067

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.162-0}{0.067}=\dfrac{0.162}{0.067}=2.4014

This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):

\text{P-value}=2\cdot P(z>2.4014)=0.0171

As the P-value (0.0171) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

At a signficance level of 0.01, there is not enough evidence to support the claim that there is significant difference between the exercise habits of Science majors and Math majors .

We want to calculate the bounds of a 99% confidence interval of the difference between proportions.

For a 99% CI, the critical value for z is z=2.576.

The margin of error is:

MOE=z \cdot s_{p1-p2}=2.576\cdot 0.067=0.1735

Then, the lower and upper bounds of the confidence interval are:

LL=(p_1-p_2)-z\cdot s_{p1-p2} = 0.162-0.1735=-0.012\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= 0.162+0.1735=0.335

The 99% confidence interval for the difference between proportions is (-0.012, 0.335).

6 0
3 years ago
Help fast! give extra points
AleksandrR [38]

Answer:

3X x 5 = 15x - 3 = 12x

7 0
3 years ago
Read 2 more answers
Solve the initial-value problem<br><br> y' = x^4 - \frac{1}{x}y, y(1) = 1.
natta225 [31]

The ODE is linear:

y'=x^4-\dfrac yx

y'+\dfrac yx=x^4

Multiplying both sides by x gives

xy'+y=x^5

Notice that the left side can be condensed as the derivative of a product:

(xy)'=x^5

Integrating both sides with respect to x yields

xy=\dfrac{x^6}6+C

\implies y(x)=\dfrac{x^5}6+\dfrac Cx

Since y(1)=1,

1=\dfrac16+C\implies C=\dfrac56

so that

\boxed{y(x)=\dfrac{x^5}6+\dfrac5{6x}}

4 0
3 years ago
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