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Vlada [557]
2 years ago
5

How many real-number solutions does the equation have?

Mathematics
2 answers:
Alexxx [7]2 years ago
8 0
I believe the correct answer would be that it has one solution which is 5. Calculating x for the quadratic equation, you will only get one value so it should be one solution. Hope this answers the question. Have a nice day.
Ahat [919]2 years ago
6 0
B) One solution.....
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PLEASE HELP ASAP!!! THIS IS MY LAST QUESTION!! SHOW WORK!! DUE IN 5 MINS
IrinaK [193]

Answer:

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Step-by-step explanation:

common sense

4 0
2 years ago
Determine and state the coordinates of the center and length of the radius of a circle whose equation is
padilas [110]
First, rewrite the equation in standard form.
The center-radius form of the circle equation<span> is in the format:
(x – h)^</span>2<span> + (y – k)^</span>2<span> = r^</span>2
<span>with the center being at the </span>point<span> (h, k) and the radius being "r".
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4 0
3 years ago
In her metalwork class, Anja cut a square of
Paul [167]

Given:

Anju cut square of tin, of edge 3.7 cm, from a larger square of edge 6.3 cm.

To find:

The area of the remaining tin.

Solution:

Area of a square is:

Area=a^2

Where, a is the edge of the square.

Area of the smaller square is:

A_1=(3.7)^2

A_1=13.69

Area of the larger square is:

A_2=(6.3)^2

A_2=39.69

The area of the remaining tin is:

A=A_2-A_1

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8 0
2 years ago
Bbbbbbbbbbbbbbbbbbbbb
mel-nik [20]

Answer:

BBAB

Step-by-step explanation:

DU DU DU DU DU DU DU DU DU

7 0
2 years ago
I don’t understand??
wlad13 [49]

Answer:

\huge\boxed{\sf x = 10}

Step-by-step explanation:

Hypotenuse = x

Base = 4

Perpendicular = \sqrt{84}

<u>Using Pythagoras Theorem:</u>

\sf H^2 = P^2 + B^2\\\\ x^2 = (\sqrt{84} )^2 + (4)^2\\\\x^2 = 84 + 16\\\\x^2 = 100\\\\Taking \ sq \ root \ on \ both \ sides\\\\x = 10\\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
7 0
3 years ago
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