How many real-number solutions does the equation have?
2 answers:
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First, rewrite the equation in standard form.
The center-radius form of the circle equation<span> is in the format:
(x – h)^</span>2<span> + (y – k)^</span>2<span> = r^</span>2
<span>with the center being at the </span>point<span> (h, k) and the radius being "r".
</span>
(x-3)^2 + (y+4)^2 = 81
From here, you can determine the center and radius. The center is at (3,-4) and the radius is 9.
The center-radius form of the circle equation<span> is in the format:
(x – h)^</span>2<span> + (y – k)^</span>2<span> = r^</span>2
<span>with the center being at the </span>point<span> (h, k) and the radius being "r".
</span>
(x-3)^2 + (y+4)^2 = 81
From here, you can determine the center and radius. The center is at (3,-4) and the radius is 9.
Given:
Anju cut square of tin, of edge 3.7 cm, from a larger square of edge 6.3 cm.
To find:
The area of the remaining tin.
Solution:
Area of a square is:
Where, a is the edge of the square.
Area of the smaller square is:
Area of the larger square is:
The area of the remaining tin is:
Therefore, the area of the remaining tin is 26 sq. cm.
Answer:
Step-by-step explanation:
Hypotenuse = x
Base = 4
Perpendicular =
<u>Using Pythagoras Theorem:</u>
Hope this helped!
<h3>~AH1807</h3>