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Georgia [21]
3 years ago
8

What is the area of a circle with a radius of 40 cm?

Mathematics
1 answer:
zvonat [6]3 years ago
7 0
The area of a circle is PiR^2
Square the radius, 40.
40 x 40 = 1600.
Multiply 1600 by Pi (3.14)
1600 x 3.14 = 5024.
5024 cm^2 is your area.
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−3(y+5)=15 someone please help me with this question my assignment is already late
AnnyKZ [126]

Answer: -10

Step-by-step explanation:

Simplifying

-3(y + 5) = 15

Reorder the terms:

-3(5 + y) = 15

(5 * -3 + y * -3) = 15

(-15 + -3y) = 15

Solving

-15 + -3y = 15

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '15' to each side of the equation.

-15 + 15 + -3y = 15 + 15

Combine like terms: -15 + 15 = 0

0 + -3y = 15 + 15

-3y = 15 + 15

Combine like terms: 15 + 15 = 30

-3y = 30

Divide each side by '-3'.

y = -10

Simplifying

3 0
3 years ago
Find the inverse of f(x) = 4x + 2.<br> The inverse of f is g(x) PLSSSS HELPPPPP!!!!!
frez [133]

Answer:

y=(x+2)/4

Step-by-step explanation:

f(x) = 4x +2 is the original equation

x = 4y + 2 is the inverse but we have to solve for y

x+2=4y

4y=x+2

y=(x+2)/4

7 0
3 years ago
Which inequality is equivalent to -m 2 15?
inysia [295]

The correct answer is option 3: m≤-15

Step-by-step explanation:

The inequalities are solved by performing operations on both sides of inequality

Given inequality is:

-m\geq 15

when an inequality is multiplied by -1 the signs of numbers on both sides are changed while the inequality operator is also reversed.

Multiplying both sides by -1 will give us:

m\leq -15

The correct answer is option 3: m≤-15

Keywords: Inequalities, Operations on inequalitites

Learn more about inequalities at:

  • brainly.com/question/4034547
  • brainly.com/question/4054269

#LearnwithBrainly

4 0
3 years ago
Pls confirm if right. Thx!
Sloan [31]

Answer:

If I am thinking right ya

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
PLS HELP ME ASAP!!!!
elena55 [62]

Answer:

2Pi/8

Step-by-step explanation:

6 0
3 years ago
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