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ANEK [815]
4 years ago
15

Triangle BIG is similar to triangle MOP . Find v .

Mathematics
1 answer:
gizmo_the_mogwai [7]4 years ago
7 0

Answer:

63:42

so this is

3:2

\frac{33}{3}  =  \frac{v}{2}

v =  \frac{2 \times 33}{3}  =  \frac{66}{3}  = 22

v=22

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Answer:

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Step-by-step explanation:

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Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

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ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

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iii.

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Step-by-step explanation:

Given

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B = Boys

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Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

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Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

7 0
3 years ago
in a Recipe, 125 ml of milk is used for every half litre of water what is the ratio of milk to water​
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Answer:

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Step-by-step explanation:

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                   = 125 ÷ 25  : 500÷25

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