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alexira [117]
3 years ago
14

Solve E=Mc2, M=3,C=6

Mathematics
2 answers:
Dmitry [639]3 years ago
6 0

You substitute M for 3 and C for 6. So you get E = (3)(6)(2) which equals 36.

mylen [45]3 years ago
4 0

All you have to do is substitute the M and C value's into the equation.

E = MC2

E = (3)(6)(2)

E = 36

Hope your thanksgiving goes well! Here's a turkey!

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which mathematical process could be used to find the length of the side of a square, given it's area​
shepuryov [24]

Answer:

\sqrt{x}

Step-by-step explanation:

the square root of what ever the area is. Area is length times width, but if all sides are the same then you just have to find the square root.

4 0
3 years ago
3⁵.2⁴.2¹.3⁶.(3²)⁴ and down (2³)².3⁶​<br>​
BARSIC [14]

Answer:

\dfrac{3^{13}}{2}

Step-by-step explanation:

Given expression:

\dfrac{3^5 \cdot 2^4 \cdot 2^1 \cdot 3^6 \cdot (3^2)^4}{(2^3)^2 \cdot 3^6}

\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:

\implies \dfrac{3^5 \cdot 2^4 \cdot 2^1 \cdot 3^6 \cdot 3^8}{2^6 \cdot 3^6}

\textsf{Apply exponent rule} \quad a^b \cdot a^c=a^{b+c}:

\implies \dfrac{3^{(5+6+8)} \cdot 2^{(4+1)}}{2^6 \cdot 3^6}

\implies \dfrac{3^{19} \cdot 2^{5}}{2^6 \cdot 3^6}

\implies \dfrac{3^{19} \cdot 2^{5}}{3^6 \cdot 2^6}

\textsf{Apply exponent rule} \quad \dfrac{a^b}{a^c}=a^{b-c}:

\implies 3^{(19-6)} \cdot 2^{(5-6)}

\implies 3^{13} \cdot 2^{-1}

\textsf{Apply exponent rule} \quad a^{-n}=\dfrac{1}{a^n}:

\implies \dfrac{3^{13}}{2^1}

\textsf{Apply exponent rule} \quad a^1=a:

\implies \dfrac{3^{13}}{2}

4 0
2 years ago
Log20 log15-log12 log5
Pani-rosa [81]
What is this exactly?
5 0
3 years ago
URGENT NEED HELP FAST LINKS WILL BE REPORTED
Butoxors [25]

Answer:

Model B

Step-by-step explanation:

First, solve what each model means:

Model A:

6 boxes, 2 shaded

2/6=1/3

1/3 is approximately 33.35

Model B:

8 boxes, 3 shaded

3/8 is 37.5%

this is the answer, but we can go ahead and check the other boxes

Model C:

5 boxes, 2 shaded

2/5 is 40%

Model D:

7 boxes, 3 shaded

3/7 is approximately 42.9%

Lmk if you have more questions!

5 0
2 years ago
HELP WITH THIS QUESTION PLEASE!
belka [17]

Answer:

23.7°

9.1~ft

Step-by-step explanation:

Formula for the area of a sector of central angle n (in degrees) and radius r:

A = \dfrac{n}{360^\circ}\pi r^2

We have:

A = 100 ft^2

r = 22 ft

We need to find:

r

100 = \dfrac{n}{360^\circ}\pi (22^2)

n = 23.7^\circ

The central angle measures 23.7°.

Formula for the length of an arcs of a circle with central angle n (in degrees) and radius r:

s = \dfrac{n}{360^\circ}2 \pi r

We have:

n = 23.7°

r = 22 ft

We need to find:

s

s = \dfrac{74.4}{360}2 \pi (22 ft)

s = 9.1~ft

6 0
3 years ago
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