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3 years ago

What is.... 4k^2-2k+4=-4 Factored?

Mathematics

1 answer:

Delvig [45]3 years ago

7 0

Answer:

4k^2-2k+4=-4 factor = 2(2k² -k +2) = -4

Step-by-step explanation:

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The rule T 5, -0.5° Ro, 1800(x, ) is applied to FGH to

Yuki888 [10]

Answer:

Step-by-step explanation:

Given rule for the multiple translations is,

$T_{5,-0.5}.R_{0.180^{\circ}}(x,y)$

Apply the rule $R_{0,180^{\circ}}$ first.

(x, y) → (-x, -y)

This rule illustrates a rotation of the triangle FGH by 180° about the origin,

Vertices of ΔFGH are,

F → (1, 1)

G → (4, 5)

H → (5, 1)

After rotation vertices of the image triangle are,

F' → (-1, -1)

G' → (-4, -5)

H' → (-5, -1)

Further apply the rule,

$T_{5,-0.5}$

(x, y) → (x + 5, y - 0.5)

By this rule of translation,

F'(-1, -1) → F"{(-1 + 5), (-1 - 0.5)}

→ F"(4, -1.5)

G'(-4, -5) → G"[(-4 + 5), (-5 - 0.5)]

→ G"(1, -5.5)

H'(-5, -1) → H"[(-5 + 5), (-1 -0.5)]

→ H"(0, -1.5)

8 0

2 years ago

WILL MARK BRAINLIEST! NEED HELP!

Mice21 [21]

Answer:

The parent graph is translated 2 to the left and up 6 units.

Step-by-step explanation:

The +2 moves the parent 2 units to the left and the + 6 moves it up 6 units.

4 0

3 years ago

Read 2 more answers

Given a right triangle with legs a, b and hypotenuse c, solve for b if a= 72 and c= 75

kotykmax [81]

Answer:

The answer is a. 21.

Step-by-step explanation:

We solve this question by using Pythagoras theorem to relate the sides of a right angled triangle.

Here,

Hypotenuse of the given triangle(c)=75

Two sides of right angled triangle are:

a=72

b=?

Then,

for a given right angled triangle abc,

Using Pythagoras theorem,

$c=\sqrt{a^{2} +b^{2} }$

Squaring on both sides,

$c^{2} =a^{2}+b^{2}$

or, $75^{2}=72^{2}+b^{2}$

or, $b^{2}=75^{2}-72^{2}$

or, $b^{2}=5625- 5184$

or, $b^{2} =441$

∴ $b=21$

So, the value of b is obtained to 21 by the use of Pythagoras theorem.

7 0

3 years ago

a fruit delivers its fruit in two types of boxes: large and small. a delivery of 3 large boxes and 5 small boxes has a total wei

Masteriza [31]

Answer:

The weight of a small box = 13.5 kg

The weight of 1 large box = 18.5 kg

Step-by-step explanation:

Let us assume the weight of a small box = m kg

And the weight of 1 large box = n kg

Now, the weight of 5 small box = 5 x (weight of 1 small box) = 5 m

Also, the weight of 3 large box = 3 x (weight of 1 large box) = 3 n

Here, 3 large boxes + 5 small boxes = of 123 kilograms

⇒ 5 m + 3 n = 123 .... (1)

Again, the weight of 2 small box = 2 x (weight of 1 small box) = 2 m

Also, the weight of 12 large box = 12 x (weight of 1 large box) = 12 n

Here, 12 large boxes + 2 small boxes = 249 kilograms

⇒ 2 m+ 12 n = 249 .... (2)

Now, solving both the given equations by ELIMINATION, we get:

5 m + 3 n = 123 x (2)

2 m+ 12 n = 249 x (-5)

we get the new set of equitation as:

10 m + 6 n = 246

- 10 m - 60 n = -1245

Adding both equation, we get

-54 n = 999

or, n = 18.5

Now, 5 m + 3 n = 123

So, 5 m = 123 -3 (18.5) = 123 - 55.5 = 67.5

⇒ m = 13.5

Hence, the weight of a small box = m kg = 13.5 kg

And the weight of 1 large box = n kg = 18.5 kg

8 0

3 years ago

a car traveled 36 miles in 45 minutes. the car traveled at a constant speed. it the car continues to travel at this rate which e

Alchen [17]

Y = 48 becuase you travelled the amount of minuets 45 x

8 0

3 years ago