Answer:
B. 80.2 square inches
Step-by-step explanation:
This figure is a composite figure made up of two rectangles (see attachment).
The area of a rectangle is denoted by: A = lw, where l is the length and w is the width.
In the top rectangle, the length is 3 and the width is 10.2, so A = 3 * 10.2 = 30.6 square inches.
The length of the bottom rectangle is 8 and the width is 6.2, so the area is A = 8 * 6.2 = 49.6 square inches.
Add these together: 30.6 + 49.6 = 80.2 square inches.
Answer:
Step-by-step explanation:
The picture of the question in the attached figure
step 1
Find the area of the large square
step 2
Find the area of the smaller white square
step 3
Find the area of the blue region
Subtract the area of the smaller white square from the area of the larger square
step 4
Find the probability
we know that
To find out the probability that a point chosen at random is in the blue region, divided the area of the blue region by the area of the larger square
so
Simplify
Answer:
-50 cents
Step-by-step explanation:
The "Winnings" random variable has values -1 and 499
The associated probabilities are P(-1)= 999/1000; P(499)=1/1000
-----------------------------
Expected Value = -1(999/1000) + 499(1/1000) = -500/1000 = -50 cents
its 300 since 20x30 is 600 and 600/2 is 300 so the answer is <em><u>300</u></em>
Firstly let's find the dimension of this large rectangle:(given)
Area of Rectangle = 660 x 66 =43,560 ft²
And we know that 1 acre = 43,560 ft², then each rectangle has an area of 1 acre & the 20 acres will correspond to 20 x 43560 = 871,200 ft²
We know that the 20 acres form a rectangle. We need to know what is their disposition:
1) We would like to know the layout of the rectangles since we have 4 possibilities FOR THE LAYOUTS
Note that W=66 & L=666 = 43,956 ft²/ unit )
lay out shape could be either:(in ft)
1 W by 20 L (Final shape Linear 66 x 13320 = 879,120) or
2 W by 10 L (Final shape Stacked 132 x 6660 = 879,120) or
4 W by 5 L (Final shape Stacked 264 x 3330 = 879,120) or
2) We would like to know the number of participants so that to allocate equal space as well as the pedestrian lane, if possible, if not we will calculated the reserved space allocated for pedestrian/visitors)
3) Depending on the shape given we will calculate the visitor space & we will deduct it from the total space to distribute the remaining among the exhibitors.
4) (SUGGESTION) Assuming it's linear, we will reserve
20ft x 13320 ft = = 266,400 ft² and the remaining 612,720 ft² for exhibitors
5) Depending on the kind of the exhibition, we will divide the 612,720 ft² accordingly
6) How can we select the space allocated for each exhibitor:
the 617,720 ft² could be written as a product of prime factors:
612720 = 2⁴ x 3² x 5 x 23 x 37
If you chose each space will be185 ft² , then we can accommodate up to 3,312 exhibitors.
Obviously you can choose any multiple of the prime factors to specify the area allocated & to calculate the number of exhibitors accordingly
