Answer:
D) x=9 ; y=3√(3)
Step-by-step explanation:





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




Therefore, x=9 and y=3√(3)
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Answer:
C, y=4.5
Step-by-step explanation:
y=2.5x-3 if you plug in 3 for x and sole the equation its y = 7.5 - 3 so then it's 4.5 equals y.
Answer:
x=6
Step-by-step explanation:
Hope it was right
So I think it’s D. So you’ll do 5 x 5 x 5 = 125 then x 2 = 250
Answer:
Case I, Case II
Step-by-step explanation:
For cases III and IV, you need the Law of Cosines.
The Law of Sines can be used when you have at least one side and the angle opposite. If you know two angles of a triangle, you know all three, so the given angles don't necessarily have to be opposite the given side if two angles are known.
The Laws of Sines can be applied to solve Case I and Case II.