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Nataly [62]
4 years ago
9

Brad knows the answer to 5 multiplied by 7 how does this help him solve the answer to 8 multiplied by 7?

Mathematics
1 answer:
dimaraw [331]4 years ago
6 0

Answer:

Breaking up the multiplicand 8 into (5+3) allows us to apply the associative property of multiplication.  See below.

Step-by-step explanation:

5*7 = 35.  We want the product 8*7.  Note that 8 = 5+3.  Thus, 8*7=(5+3)(7) = 35 + 21, or 56.

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Tyrone claims that the first step to simplify this expression
ser-zykov [4K]

Answer:

1/(m^4*n^2

Step-by-step explanation:

The given expression is

(m^2*n^-3)/(m^6*n^-1)

Tyrone's approach.

Raising the expression to the 3rd power will not help. It will make the expression more complicated.

Alisha's approach.

(m^2*n^-2)/(m^6*n^-1)

= m^(2-6)*n^(-3+1)

= m^-4*n^-2

= 1/(m^4*n^2)

Alisha's approach will simplify the expression to 1/(m^4*n^2

4 0
3 years ago
"13 less than two-thirds of a number"
Sindrei [870]
The answer to your question is 13<2/3
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3 years ago
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What is the value of -(-(-(-(4)?
Mumz [18]

Answer:

4

Step-by-step explanation:

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3 years ago
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Two professors at a nearby university want to co-author a new textbook in either economics or statistics. They feel that if they
WARRIOR [948]

Answer:

0.3 or 30%

Step-by-step explanation:

The professors will only seek a smaller publisher if they cannot place the statistics book with a major publisher. If the probability of getting a major publisher is 40% and the probability of getting a smaller publisher is 50%, then the probability that the statistics book would wind up being placed with a smaller publisher is given by:

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3 0
4 years ago
What is the area?<br> 20 in<br> 25 in<br> square inches
slava [35]

Answer:

<em>2</em><em>5</em><em>0</em><em> </em><em>in </em><em>sq</em>

Step-by-step explanation:

<em>Here's</em><em> the</em><em> solution</em>

<em>=</em><em>></em><em> </em><em>Base </em><em>=</em><em> </em><em>2</em><em>5</em><em>i</em><em>n</em><em> </em>

<em>=</em><em>></em><em> </em><em>Height</em><em> </em><em>=</em><em> </em><em>2</em><em>0</em><em>i</em><em>n</em>

<em>=</em><em>></em><em>We </em><em>need</em><em> to</em><em> </em><em>find </em><em>out</em><em> area</em><em> of</em><em> traingle</em>

<em>=</em><em>></em><em> </em><em>Area</em><em> of</em><em> </em><em>traingle </em><em>=</em><em> </em><em>1</em><em>/</em><em>2</em><em>*</em><em>base </em><em>*</em><em>height</em><em> </em>

<em>=</em><em>></em><em> </em><em>Area</em><em> </em><em>=</em><em> </em><em>1</em><em>/</em><em>2</em><em>*</em><em>2</em><em>0</em><em>*</em><em>2</em><em>5</em><em> </em>

<em>=</em><em>></em><em> </em><em>Area</em><em>=</em><em> </em><em>2</em><em>5</em><em>0</em><em> </em><em>in </em><em>sq</em>

<em>hope</em><em> it</em><em> helps</em><em>. </em><em> </em><em>^</em><em>_</em><em>^</em>

7 0
3 years ago
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