Answer:
<u>Question 1</u>
The function
is one-to-one, so it does have an inverse.
The inverse of +6 is -6, so 
Therefore, g(x) is the inverse of f(x).
<u>Question 2</u>
The function
is one-to-one, so it does have an inverse.
To find the inverse, replace f(x) with y:

Rearrange the equation to make x the subject:



Replace x with
and y with x:

Therefore, g(x) is the inverse of f(x).
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Answer:
D) x and ( y z + 1 2 ) are independent of each other
Step-by-step explanation:
Assuming this is not intended to be describing a function named x with an argument of yz+12, the variables in any expression are assumed to be independent of each other, unless additional information is provided showing their dependencies.
Here, there is no such additional information, so we must assume ...
x and (yz +12) are independent of each other
_____
<em>Additional comment</em>
The assumption stated in the answer is intended to ensure we're not concerned with something of the form ...
g(x)
which is an expression saying 'g' is dependent on 'x'. If we know 'g' is a function name, then g(yz+12) will make 'g' be dependent on (yz+12).
Similarly, if x(a) is intended to mean that x is a function of 'a', then the corresponding x(yz+12) will mean that x is dependent on (yz+12). This would be quite unusual, since letters toward the end of the alphabet are usually used for variable names, while letters in the middle of the alphabet are used for function names.
Answer:
A.
Step-by-step explanation:
you have to find the discriminant
b²-4ac for each equation
if discriminant < 0 no real solutions because will be negative under the squareroot whhan you try to find the roots
if discriminant = 0 there is only one solution
if discriminant > 0 two real solutions
for your given problems
A. discriminant =(-2)²-4*2*15 will be negative
That's a rectangular prism.
And the formula to find the volume of a rectangular prism is:

Plug in what we know:

Multiply the three numbers together:
You have to plug in a random y value and use algebra to solve for x. It is impossible to do without at least one point for y.