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netineya [11]
3 years ago
10

Simplify the following expression 2x − 6y + 3x2 + 7y − 14x

Mathematics
1 answer:
Setler [38]3 years ago
4 0
2x - 6y + 3x² + 7y - 14y = 3x² + (2x - 14x) + (-6y + 7y) = 3x² - 12x + y
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please help me with this math problem, the question is on the picture that i attached, ill mark brainliest if the answer is corr
dsp73

Answer:

cos z = 35 / 37

Step-by-step explanation:

cos z is the ratio of the adjacent side of a triangle (the side adjacent to angle z to the hypotenuse:

cos z = (adj. side) / (hypotenuse)

Here we have cos z = 35 / 37

7 0
3 years ago
What does not represent the quotient of 17 divided by 10?
amm1812
17-10= j      i really don't know i just guessed  
7 0
3 years ago
Describe the end behavior of the function. f(x)=x^3+11x^2+35x+30
Lelechka [254]
To determine end behavior, we only have to look at the leading term.

First, the leading term is positive, so we won't have to negate anything.

The leading term has a power that is odd.

Since the exponent is odd, this means that the function goes to positive infinity as x goes to positive infinity.

This also means that the function goes to negative infinity as x goes to negative infinity.

Those are the end behaviors.

Have an awesome day! :)
4 0
3 years ago
Can someone help I’m not good with word problems
pickupchik [31]

Answer:

I agree that this question can be confusing:

Apparently point A and point B must be on the same straight line (measured from the light house or the question would be nonsensical)

tan 13 = H / DA      where H is height of lighthouse

tan 8 = H / DB       tangent measured from point B

tan 13 / tan 8 = DB / DA

DB = .2309 / .1405 * 1279 = 2101 ft

DB - DA = 2101 - 1279 = 822.0 ft

3 0
2 years ago
Add. write your answer in simplest form.<br> -4 _/135 + 7 _/15
Zarrin [17]

\huge\quad\qquad\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  - 4 \sqrt{135} + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 4 \sqrt{5 \times3 \times 3 \times 3}  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \:( - 4 \times 3) \sqrt{5 \times 3}  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 12 \sqrt{15 }  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 5 \sqrt{15}

7 0
2 years ago
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