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Anni [7]
3 years ago
10

Solve: 6 yd. 9 ft 4 in. × 2

Mathematics
2 answers:
Lorico [155]3 years ago
5 0

Answer:

The value of the provided measurement 6 yd. 9 ft 4 in. × 2 is 12 yd. 18 ft 8 in.

Step-by-step explanation:

Consider the provided measurements.

6 yd. 9 ft 4 in. × 2

Here, the sign "×" represents the measurement is multiplied by 2.

So multiply each number by 2 as shown.

6 × 2 yd. 9 × 2 ft 4 × 2 in.

12 yd. 18 ft 8 in.

Hence, the value of the provided measurement 6 yd. 9 ft 4 in. × 2 is 12 yd. 18 ft 8 in.

Kazeer [188]3 years ago
4 0
Okay so multiply everything by 2 6yrds×2=12yrds. 9ft×2=18ft. 4in×2=8in. So the answer is: 12yrds 18ft 8in
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Is n÷12=36,n=108 true or false​
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Answer:

False

Step-by-step explanation:

n÷12=36

n=36*12

hence n=432

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2 years ago
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The probability that a certain hockey team will win any given game is 0.3723 based on their 13 year win history of 385 wins out
Whitepunk [10]

Answer:

0.1505 = 15.05% probability that the hockey team wins 6 games in November

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the team wins, or it does not. The probability of winning a game is independent of winning other games. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that a certain hockey team will win any given game is 0.3723

So p = 0.3723

12 games in November

So n = 12

What is the probability that the hockey team wins 6 games in November?

This is P(X = 6)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{12,6}.(0.3723)^{6}.(1-0.3723)^{6} = 0.1505

0.1505 = 15.05% probability that the hockey team wins 6 games in November

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In the given diagram abc is a right angle with DG CB segment AB is divided into four equal parts . The coordinates of point F ar
pickupchik [31]

Answer:

E(3.75,-2.5)

G(-0.75,-3)

Step-by-step explanation:

Point E is the midpoint of the segment AB, then it has coordinates

\left(\dfrac{-3+6}{2},\dfrac{-1+(-3)}{2}\right)=\left(\dfrac{3}{2},-2\right).

Point F is the midpoint of the segment EB, then it has coordinates

\left(\dfrac{\frac{3}{2}+6}{2},\dfrac{-2+(-3)}{2}\right)=\left(\dfrac{15}{4},-\dfrac{5}{2}\right)=(3.75,-2.5).

Let S be the midpoint of segment CB, then it has coordinates

\left(\dfrac{-3+6}{2},\dfrac{-3+(-3)}{2}\right)=\left(\dfrac{3}{2},-3\right).

Point G is the midpoint of segment CS, then its coordinates are

\left(\dfrac{\frac{3}{2}+(-3)}{2},\dfrac{-3+(-3)}{2}\right)=\left(-\dfrac{3}{4},-3\right)=(-0.75,-3).

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