r > 0 = r is greater than 0
r ≤ 8 = r is less than and equal to 8
0 ≤ r ≤ 8
Answer:
Power generated = 4.315 kW
Step-by-step explanation:
Given,
- speed of wind when enters into the turbine, V = 12 m/s
- speed of wind when exits from the turbine, U = 9 m/s
- mass flow rate of the wind, m = 137 kg/s
According to the law of conservation of energy
Energy generated = change in kinetic energy
Since, the air is exiting at same elevation. So, we will consider only kinetic energy.
Energy generated in one second will be given by,


=4315.5 J
= 4.315 kJ
So, energy is generated in one second = 4.315 kJ
Power generated can be given by,

And the energy is generated is already in per second so power generated will be 4.315 kW.
Answer:
2
Step-by-step explanation:
S(t) = -4 - 2t
s'(t) = -2
s'(6) = -2