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Alina [70]
3 years ago
5

Each flyer costs $0.25. Our budget is $555. It will cost $115 for other supplies. How much money do we have to spend on flyers?

Mathematics
1 answer:
Bogdan [553]3 years ago
7 0

Answer:

We have $440 to spend on fliers

Step-by-step explanation:

Budget = supplies + fliers

555 = 115 + fliers

Subtract 115 from each side

555-115 = 115-115 + fliers

440 = fliers

We have $440 to spend on fliers

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damaskus [11]
La of sine:

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sin(64.5) = sin(180°-64.5°) ==> B = 64.5° or 115.5°
6 0
2 years ago
Check all of the ordered pairs that satisfy the equation below.y=2/5x
zvonat [6]

We are going to do this step by step:

Let's start with option A

A.

X = 25 and Y = 5/2

y=\frac{2}{5}\cdot x=\frac{2}{5}\cdot25=\frac{2\cdot25}{5}=\frac{50}{5}=\frac{5\cdot10}{5\cdot1}=10

In this case, when X = 25 , then Y = 10 ,which is different to 5/2

B.

X = 14 , Y = 35

y=\frac{2}{5}\cdot14=\frac{28}{5}

In case, when X = 14, then Y = 28/5, which is different to 35

C.

X = 40 , Y = 24

y=\frac{2}{5}\cdot40=\frac{80}{5}=16

Similarly, in this case, when X = 40, then Y = 16, which is different to 24

D.

X = 10 , Y=4

y=\frac{2}{5}\cdot10=\frac{20}{5}=4

Now, in this case, we can see that when X = 10, then Y = 4 which is the same as the given value of Y

E.

X = 50 , Y = 20

y=\frac{2}{5}\cdot50=\frac{100}{5}=20

In this case, the values of Y are also the same.

F.

X = 30 , Y = 12

y=\frac{2}{5}\cdot30=\frac{60}{5}=12

Again, in this case, the values of Y are the same, so the pair satisfies the equation.

In conclusion: options D, E and F satisfy the equation

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3 years ago
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The table below shows pairs of value that satisfy a linear function.
neonofarm [45]

Answer:

-27

Step-by-step explanation:

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3 years ago
Haley is twice as old as Riley. The sum of their ages is 39. Write an equation that represents (x) , Riley's age.
kenny6666 [7]

Answer:

X=39×2. Answer: 39×2= 78

6 0
3 years ago
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