Answer:
106.8 in.
Step-by-step explanation:
The circumference of a circle:
C = 2πr
Substitute the given information into the formula.
C = 2(3.14)(17) = 106.8
Answer:
0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.
Step-by-step explanation:
Exponential distribution:
The exponential probability distribution, with mean m, is described by the following equation:

In which
is the decay parameter.
The probability that x is lower or equal to a is given by:

Which has the following solution:

The probability of finding a value higher than x is:

Mean of 4 minutes
This means that 
Find the probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot:
This is:

In which



0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.
Answer:
The bottom left answer choice displays an outlier
Step-by-step explanation:
Answer:
15
Step-by-step explanation:
5 ! = 120
Since 5 ! = 5 × 4 × 3 × 2 × 1, then
5 × 3 = 15 is the greatest odd factor of 5 !
(a) Take the Laplace transform of both sides:


where the transform of
comes from
![L[ty'(t)]=-(L[y'(t)])'=-(sY(s)-y(0))'=-Y(s)-sY'(s)](https://tex.z-dn.net/?f=L%5Bty%27%28t%29%5D%3D-%28L%5By%27%28t%29%5D%29%27%3D-%28sY%28s%29-y%280%29%29%27%3D-Y%28s%29-sY%27%28s%29)
This yields the linear ODE,

Divides both sides by
:

Find the integrating factor:

Multiply both sides of the ODE by
:

The left side condenses into the derivative of a product:

Integrate both sides and solve for
:


(b) Taking the inverse transform of both sides gives
![y(t)=\dfrac{7t^2}2+C\,L^{-1}\left[\dfrac{e^{s^2}}{s^3}\right]](https://tex.z-dn.net/?f=y%28t%29%3D%5Cdfrac%7B7t%5E2%7D2%2BC%5C%2CL%5E%7B-1%7D%5Cleft%5B%5Cdfrac%7Be%5E%7Bs%5E2%7D%7D%7Bs%5E3%7D%5Cright%5D)
I don't know whether the remaining inverse transform can be resolved, but using the principle of superposition, we know that
is one solution to the original ODE.

Substitute these into the ODE to see everything checks out:
