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BartSMP [9]
4 years ago
13

Which is an algebraic expression for 5 more than z? 5z Z+5 5z+5 5-z

Mathematics
2 answers:
svetoff [14.1K]4 years ago
5 0
"5 more than z"  means 5+z, or z+5.


what the other mean is as follows:

<span>5z   "5 times z"
Z+5  
5z+5  " 5 more 5 times z"
5-z    "z less than 5 "


Answer: </span>z+5
Mumz [18]4 years ago
4 0
Z+5 is the problem for sure
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5(x-2)^2-29=-14 what does x equal
eimsori [14]

Answer:

x = 2+\sqrt{3}

Step-by-step explanation:

5(x-2)^2= 15 ←add 29 on both sides

(x-2)^2= 3  ← divide by 5 on both sides

x-2= \sqrt{3}   ← find the sq root of both sides

x= 2+\sqrt{3}   ← add 2 on both sides

8 0
3 years ago
HELP! Ev evaluate the square root of 16 plus the square root of 29, correct to two decimal places.
Stella [2.4K]

Answer:

\sqrt{16} +\sqrt{29} =9.39

Step-by-step explanation:

\sqrt{16} =4

\sqrt{29} ≅ 5.39

4+5.39=9.39

6 0
3 years ago
Read 2 more answers
Youre amazing!!! could you help me? 50 points!!! Write an expression that can be used to produce vector d from vector c, and exp
andrew-mc [135]

Answer:

Multiply vector c by the scalar -1/2.

Step-by-step explanation:

Look at vector c.

It has an x component of 4 and a y component of 4.

You can write vector c as a sum of its components using unit vectors in the x direction (i) and in the y direction (j).

c = 4i + 4j

Now look at vector d, and write it also as a sum of its x and y components.

d = -2i - 2j

Now ask yourself, what operation do I do to 4 to end up with -2?

One answer is to multiply 4 by -1/2.

d = (-1/2)c = (-1/2)(4i) + (-1/2)(4j) = -2i - 2j

That worked. By multiplying vector c by the scalar -1/2, you end up with vector d.

8 0
2 years ago
What is the midpoint of the line segment with endpoints (-2,-2) and (4.6)?
erma4kov [3.2K]

Answer:

Step-by-step explanation:

(-2,2) ...x1 = -2 and y1 = 2

(4,6)..x2 = 4 and y2 = 6

midpoint formula :

m = ((x1 + x2) / 2 , (y1 + y2) / 2)

m = ((-2 + 4) / 2 , (2 + 6) / 2)

m = 2/2 , 8/2

m = (1,4) <===

5 0
4 years ago
Solve y=-3x² + 4.5x – 20<br> Use the Quadratic formula
statuscvo [17]

Answer:

x=0.75 \pm 2.47067i

Step-by-step explanation:

Quadratic Formula: x=\frac{-b \pm \sqrt{b^2-4ac} }{2a}

√-1 is imaginary number i

Step 1: Define

y = -3x² + 4.5x - 20

a = -3

b = 4.5

c = -20

Step 2: Substitute and Evaluate

x=\frac{-4.5 \pm \sqrt{4.5^2-4(-3)(-20)} }{2(-3)}

x=\frac{-4.5 \pm \sqrt{20.25-240} }{-6}

x=\frac{-4.5 \pm \sqrt{-219.75} }{-6}

x=\frac{-4.5 \pm \sqrt{219.75}(\sqrt{-1} ) }{-6}

x=\frac{-4.5 \pm i\sqrt{219.75} }{-6}

x=\frac{4.5 \pm i14.824 }{6}

x=0.75 \pm 2.47067i

7 0
3 years ago
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