Answer:
93>4-x5 YTILAUQENI EVLOS
Step-by-step explanation:
Answer:
brqnficojeuiyrjnxsoihgfyufhrbjenfrvbwejifwhbfuiwebf
Step-by-step explanation:
Answer:
Step-by-step explanation:
We can get this done by using the code
def digits(n):
count = 0
if n == 0:
return 1
while (n > 0):
count += 1
n= n//10
return count
Also, another way of putting it is by saying
def digits(n):
return len(str(n))
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print(digits(25)) # Should print 2
print(digits(144)) # Should print 3
print(digits(1000)) # Should print 4
print(digits(0)) # Should print 1
Doing this way, we've told the system to count the number of figures that exist in the number. If it's 1000 to 9999, then it records it as 4 digits. If it's 100 - 999, then it records it as 3 digits. If it's 10 - 99, it records as 2 digits. If it's 0 - 9, then it has to record it as a single digit.
Thanks
It’s 20 I believe. All together it should be 160 so you add 118 and 22 to get 140. Then subtract that from 160 and you get 20.
Answer:
97 and 1/8
Step-by-step explanation:
(4 + 7 + 5 + 5 + 2) + (14 5/8 + 14 3/4 + 14 7/8 + 15 + 15 1/8)
23 + (14 5/8 + 14 3/4 + 14 7/8 + 15 + 15 1/8)
23 + 74 1/8
97 and 1/8