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tamaranim1 [39]
4 years ago
9

Compare a modern baseball game with a baseball game in the 1800s

Advanced Placement (AP)
1 answer:
dimulka [17.4K]4 years ago
3 0

1. No popcorn

2.Better stadium

3.Better players

3. No jumbo screens

4.No mascot

5. Not on T.V

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For the equilibrium: 2 NO​ (g) ​ ⇌ N​ 2(g)​+ O​ 2(g)​at 300 K, the equilibrium constant, Kc, is 0.185. If 1.45 moles each of N​
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Answer: The concentrations of N_2,O_2\text{ and }NO at equilibrium are 0.112 M, 0.112 M  and 0.260 M

Explanation:

Moles of N_2 = 1.45 mole

Moles of  O_2 = 1.45 mole

Volume of solution = 6.00 L

Initial concentration of N_2 = \frac{moles}{Volume}=\frac{1.45mol}{6.00L}=0.242M

Initial concentration of O_2 = \frac{moles}{Volume}=\frac{1.45mol}{6.00L}=0.242M

The given balanced equilibrium reaction is,

           2NO(g)\rightleftharpoons N_2(g)+O_2(g)

Initial conc.          0 M             0.242 M              0.242 M  

At eqm. conc.     (2x) M      (0.242-x) M        (0.242-x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[N_2]\times [O_2]}{[NO]^2}  

Now put all the given values in this expression, we get :

0.185=\frac{(0.242-x)^2}{(2x)^2}

By solving the term 'x', we get :

x = 0.130

Thus, the concentrations of at equilibrium are :

Concentration of = (0.242-x) M  = (0.242-0.130) M = 0.112 M

Concentration of = (0.242-x) M  = (0.242-0.130) M = 0.112 M

Concentration of = 2x M = = 0.260 M

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So transferring from Northeastern university to umass lowell

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