Question

QF Q1.) Solve the triangle.

Answer 1

C=180-A-B=180-69-40=71deg.

by sine rule

b/sinB=a/sinA
b=a/sinA*sinB
=15/sin(69)*sin(40)
= 10.33

c/sinC=a/sinA
c=a/sinA*sinC
=15/sin(69)*sin(71)
= 15.19

Answer 2

Sum of interior angles in a triangle is 180 deg.

so angle C = 180 - A - B

=180 - 69 -  40

=71deg.

Use the sine rule in a triangle - sinA / a = sinB / b

b = a * sinB / sinA

=15 * sin(40) / sin(69)

=10.3

Similarly sinC / c = sinA / a

c = a * sinC / sinA

=13 * sin(71) / sin(69)

=15.2