Answer:
Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.
Let Q be the point onthe circle in which, tangent make 90° with radius at Q.
PQ = 8 and OQ = 6
we get a right angled triangle PQO right angled at Q.
so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==
therefore OP =10cm
we need nearest point from P, which is PA
PA = OP - OA= 10 -6=4cm
Answer:
you would use 20 quarters and 14 dimes
Step-by-step explanation:
25*20=500
10*14=140
5.00+1.40=6.40
Answer:
its {0,1,2,3,4,5......}
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
The original is L, if it was roated 180 degrees clockwise it would be in the same spot
Answer:
7 -1 6 | -8
7 -5 7 | 1
0 1 -4 | -5
Step-by-step explanation:
Note that there are four columns in this system, representing the variables x, y and z and constants. So the given matrix pattern is appropriate: It has three columns for the coefficients of x, y and z and one column for the constants.
We need only identify the coefficients and transfer them into the appropriate boxes of the matrix pattern.
We get:
7 -1 6 -8
7 -5 7 1
0 1 -4 -5
