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vivado [14]
2 years ago
13

Type the correct answer in the box. Find the value of x in this polygon. x =

Mathematics
1 answer:
STALIN [3.7K]2 years ago
7 0
Where’s the x first
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Michael, whose eyes are five feet off the ground, is standing 26 feet away from the base of a building, and he looks up at a 65°
yawa3891 [41]

Answer:

Dear user,

Answer to your query is provided below

The building is 60.77 ft tall.

Step-by-step explanation:

Explanation is provided below in the image attached

3 0
2 years ago
Help me please chile
jekas [21]

Answer:

1 neither

2 supplementary

3 supplementary

Step-by-step explanation:

7 0
2 years ago
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Solve x and y 3x-4y=18,9x-2y=12
Rudiy27

Answer:

3x-4y=18

1xy=18

xy=18 ans

4 0
3 years ago
Read 2 more answers
Ricardo took the following steps to simplify the expression below but was surprised to hear that his answer was incorrect. Which
Xelga [282]

You have not given us any of the steps that Ricardo took to simplify the
expression, and you also haven't given us the list of choices that includes
the description of his mistake, so you're batting O for two so far. 
Other than those minor details, the question is intriguing, and it certainly
draws me in.

If Ricardo made a mistake in simplifying that expression, I'm going to say that
it was most likely in the process of removing the parentheses in the middle. 

Now you understand that this is all guess-work, because of all the stuff that you
left out when you copied the question, but I think he probably forgot that the  3x 
operates on everything inside the parentheses.

He probably wrote that  3x (x-3)  is

either    3x² - 3
     or       x - 9x .

In reality, when properly simplified,

       3x (x - 3)  =  3x² - 9x .


3 0
2 years ago
Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca
Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

\frac{dQ}{dt} = -rt

Which has the following solution:

Q(t) = Q(0)e^{-rt}

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that Q(6) = (1-0.03)Q(0) = 0.97Q(0). We use this to find r.

Q(t) = Q(0)e^{-rt}

0.97Q(0) = Q(0)e^{-6r}

e^{-6r} = 0.97

\ln{e^{-6r}} = \ln{0.97}

-6r = \ln{0.97}

r = -\frac{\ln{0.97}}{6}

r = 0.0051

So

Q(t) = Q(0)e^{-0.0051t}

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

Q(t) = Q(0)e^{-0.0051t}

0.5Q(0) = Q(0)e^{-0.0051t}

e^{-0.0051t} = 0.5

\ln{e^{-0.0051t}} = \ln{0.5}

-0.0051t = \ln{0.5}

t = -\frac{\ln{0.5}}{0.0051}

t = 135.9

The half-life of the radioactive substance is 135.9 hours.

6 0
2 years ago
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