The slopes of perpendicular lines are negative reciprocals.The slope of the given line is 4.The slope of the perpendicular is -1/4.
Now we need to find the equation of a line that has slope -1/4 and passes through the point (4, 20).
We use the point-slope form of the equation of a line, where m = slope, and the point is (x1, y1).
y - y1 = m(x - x1)
y - 20 = -1/4(x - 4)
-4y + 80 = x - 4
x + 4y = 84
The correct answer is 4. 4/5 + 5/7
Hope this helps :)
Answer:
168 in cubed
Step-by-step explanation:
This should be correct if not tell me ill redo it :)
Use format: y = mx + b
m = slope
Y = 4x + 12
The slope is 4
Two factors of x²-12x+36 are
(x-6) and (x-6)
Solution;
x²-12x +36
x²-6x -6x +36 ( split -12x in two parts such that if add them we will get-12x and if multiply will get 36x²)
Taking x common from first two terms and 6 from next two terms
x(x-6) -6(x -6)
taking (x-6) common
(x-6)(x-6)