3 years ago

3x-7=3x+1 solve for x

Mathematics

2 answers:

andrew11 [14]3 years ago

8 0

Answer:

It will be no solution the reason is you have to subtract 3x from both sides and the simplify -7=1

Step-by-step explanation:

IgorC [24]3 years ago

8 0

3x-7=3x+1
-1
3x-8=3x
-3x. -3x
-8=x

You might be interested in

Solve the equation: c + 4c = -90

Liono4ka [1.6K]

Answer:

c= -18

Step-by-step explanation:

c+4c= -90

combine like terms

5c= -90

Divide by 5 on both sides

c= -18

6 0

3 years ago

Read 2 more answers

If sin(x) = 5/13, and x is in quadrant 1, then tan(x/2) equals what?

Rufina [12.5K]

$x$ is in quadrant I, so $0$ , which means $0$ , so $\dfrac x2$ belongs to the same quadrant.

Now,

$\tan^2\dfrac x2=\dfrac{\sin^2\frac x2}{\cos^2\frac x2}=\dfrac{\frac{1-\cos x}2}{\frac{1+\cos x}2}=\dfrac{1-\cos x}{1+\cos x}$

Since $\sin x=\dfrac5{13}$ , it follows that

$\cos^2x=1-\sin^2x\implies \cos x=\pm\sqrt{1-\left(\dfrac5{13}\right)^2}=\pm\dfrac{12}{13}$

Since $x$ belongs to the first quadrant, you take the positive root ( $\cos x>0$ for $x$ in quadrant I). Then

$\tan\dfrac x2=\pm\sqrt{\dfrac{1-\frac{12}{13}}{1+\frac{12}{13}}}$

$\tan x$ is also positive for $x$ in quadrant I, so you take the positive root again. You're left with

$\tan\dfrac x2=\dfrac15$