Answer:
Step-by-step explanation:
F(x) = 18-x^2 is a parabola having vertex at (0, 18) and opening downwards.
g(x) = 2x^2-9 is a parabola having vertex at (0, -9) and opening upwards.
By symmetry, let the x-coordinates of the vertices of rectangle be x and -x => its width is 2x.
Height of the rectangle is y1 + y2, where y1 is the y-coordinate of the vertex on the parabola f and y2 is that of g.
=> Area, A
= 2x (y1 - y2)
= 2x (18 - x^2 - 2x^2 + 9)
= 2x (27 - 3x^2)
= 54x - 6x^3
For area to be maximum, dA/dx = 0 and d²A/dx² < 0
=> 54 - 18x^2 = 0
=> x = √3 (note: x = - √3 gives the x-coordinate of vertex in second and third quadrants)
d²A/dx² = - 36x < 0 for x = √3
=> maximum area
= 54(√3) - 6(√3)^3
= 54√3 - 18√3
= 36√3.
Answer:
The revised drawing be larger or smaller than your original one
Step-by-step explanation:
The revised drawing be larger or smaller than your original one.
Because a drawing at a scale of:
- 1:10 means that the object is 10 times smaller than in real life scale 1:1
- 1: 8 means that the object is 8 times smaller than in real life scale 1:1
So it means the revised drawing be larger or smaller than your original one
Step-by-step explanation:
I think you can solve this question now
Answer:
y = x - 5
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = x - 3 ← is in slope- intercept form
with slope m = 1
• Parallel lines have equal slopes, hence
y = x + c ← is the partial equation of the parallel line.
To find c substitute (3, - 2) into the partial equation
- 2 = 3 + c ⇒ c = - 2 - 3 = - 5
y = x - 5 ← equation of parallel line
