Technically the endpoints will be intersection of first endpoint between x=1 and y=-1second endpoint between x=-2 and y=2
so they are 1-i and -2+2i
The "relative frequency" is
(number of times a blue marble came out)
divided by
(total number of trials before everybody got bored and quit) .
-- The relative frequency of blue was (20/60) = (33 and 1/3) % .
(Even though 38.5% of the marbles in the jar are blue,
they didn't get picked that often.)
-- The relative frequency of green was (18/60) = 30 % .
(Even though only 26.9% of the marbles in the jar are green,
they got picked more often than that.)
-- The relative frequency of red was (22/60) = (36 and 2/3) % .
(Even though 42.3% of the marbles in the jar are red,
they didn't get picked that often.)
Answer:
Para trasladar 300 cajones, las dos opciones cuestan los mismo. Son indiferentes entre si.
Step-by-step explanation:
<u>Dada la siguiente información:</u>
<u></u>
Cantidad de cajones= 300
Opción A:
Camiones con capacidad para 50 cajones que cobran 150 por viaje.
Cantidad de camiones= 300/50= 6
Opción B:
Camiones con capacidad de 60 cajones por 180 por viaje.
Cantidad de camiones= 300/60= 5
<u>Debemos calcular el costo total de cada opción y elegir la de menor costo.</u>
Costo total A= 150*6= $900
Costo total B=180*5= $900
Para trasladar 300 cajones, las dos opciones cuestan los mismo. Son indiferentes entre si.
Answer:
12 boys
Step-by-step explanation:
From the above question:
Number of boys = 3
Number of girls = 2
Boys: Girls
3:2
Let :
a = boys
b = girls
Hence, a : b = 3 : 2
a/b = 3/2
Cross Multiply
2a = 3b .......... Equation 1
a = 3b/2
If four more girls join the class, there will be the same number of boys and girls
Hence,
a: b + 4 = 3 : 3
a/b + 4 = 3/3
Cross Multiply
3a = 3(b + 4)
3a = 3b + 12 ........ Equation (2)
From Equation 1: a = 3b/2
Substitute 3b/2 for a in Equation 2 we have:
3a = 3b + 12 .........Equation 2
3(3b/2) = 3b + 12
9b/2 = 3b + 12
Cross Multiply
9b = 2(3b + 12)
9b= 6b + 24
9b - 6b = 24
3b = 24
b = 8
Substitute 8 for b in Equation 1
a = 3b/2
a = 3 × 8/2
a = 24/2
a = 12
Therefore, the number of boys in the class is 12
No, b is the y-intercept, m is the slope
