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Cloud [144]
4 years ago
5

Given that , where would the orthocenter be located?

Mathematics
2 answers:
frozen [14]4 years ago
4 0
We have circumcentre , incenter and orthocentre

orthocenter are the intersection points all the altitudes

for all triangles i.e actute , obtuse and right anled...orthocentre lies inside the triangle always

hope it helped 

zmey [24]4 years ago
3 0
We know, Orthocenter is <span> the point of concurrency of the three altitudes of a triangle which always meet inside the figure.

In short, Your Answer would be Option B) "Inside the Triangle"

Hope this helps!</span>
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2- 1/2n=3n+16<br><br> I need you to solve the whole equation step by step
Alex Ar [27]

Answer:

n = -4

Step-by-step explanation:

2 - 1/2 n = 3n + 16

Combine the constants by subtracting 2 from both sides.

-1/2n = 3n + 14

Combine the variable by subtracting 3n from both sides.

-7/2n = 14

Multiply both sides by 2 to simplify the fraction.

-7n = 28

Isolate n by dividing by -7 on both sides.

n = -4

Check.

2 - 1/2(-4) = 3(-4) + 16

2 + 2 = -12 + 16

4 = 4

Your answer is correct.

3 0
3 years ago
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Mr. Lim read 10 pages. Mr Smith read 15 pages. How many did Mr. Want read?
vazorg [7]
It doesn't say anything about him.
6 0
4 years ago
Read 2 more answers
The amount of $180.00 is what percent greater than $135.00
olga nikolaevna [1]
Percent change = ((new value) - (old value))/(old value) × 100%
  = (180 -135)/135 × 100%
  = 33 1/3%

180 is about 33% greater than 135.
8 0
4 years ago
Please help!! i will help you back!!
NeX [460]

Answer:

c = 50

Step-by-step explanation:

Using the Pythagorean Theorem:

Plug in the values of a = 14, and b = 48

a^{2} +b^{2} =c^{2}\\14^{2} +48^{2} =c^{2}  \\c^{2} = 2500\\c = \sqrt{2500} \\c = 50

7 0
3 years ago
Write the equation of the line in slope-intercept form. m=5/9 y-intercept (0,2) 2 The equation of the line in slope-intercept fo
aniked [119]

Answer:

y = (5/9)x + 2

Step-by-step explanation:

Slope intercept form is

y = mx + b then plug in the values

y = (5/9)x + 2

4 0
3 years ago
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