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gulaghasi [49]
3 years ago
13

Karen is opening a new container of one-a-day vitamins that holds 250 vitamins. Each vitamin has 20 mg of phosphorus, which make

s up 2% of her daily need. How much phosphorus does Karen need in a day? Give your answer in scientific notation.
Mathematics
1 answer:
Elan Coil [88]3 years ago
4 0
Karen needs 230 mg of Phosphorus
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Multiply and simplify. (2x - 1)(6x - 7)
Kryger [21]

Answer:

D) 12x² - 20x + 7

Step-by-step explanation:

Use FOIL when multiplying 2 binomials...

FOIL is Firsts, Outsides, Insides, Lasts.  It's the order in which you multiply the numbers in the binomials...

(2x - 1)(6x - 7)    

Firsts:  (2x)(6x) = 12x²

Outsides:  (2x)(-7) = -14x

Insides:  (-1)(6x) = -6x

Lasts:  (-1)(-7) = 7

Now add them up...

12x² - 14x - 6x + 7

    12x² - 20x + 7

8 0
3 years ago
If a giant microwave is 9 feet long, 6 feet wide, and 3 feet high, what is its volume in cubic yards?
Anika [276]

Answer:

322

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
In a football or soccer game, you have 22 players, from both teams, in the field. what is the probability of having at least any
Tamiku [17]

We can solve this problem using complementary events. Two events are said to be complementary if one negates the other, i.e. E and F are complementary if

E \cap F = \emptyset,\quad E \cup F = \Omega

where \Omega is the whole sample space.

This implies that

P(E) + P(F) = P(\Omega)=1 \implies P(E) = 1-P(F)

So, let's compute the probability that all 22 footballer were born on different days.

The first footballer can be born on any day, since we have no restrictions so far. Since we're using numbers from 1 to 365 to represent days, let's say that the first footballer was born on the day d_1.

The second footballer can be born on any other day, so he has 364 possible birthdays:

d_2 \in \{1,2,3,\ldots 365\} \setminus \{d_1\}

the probability for the first two footballers to be born on two different days is thus

1 \cdot \dfrac{364}{365} = \dfrac{364}{365}

Similarly, the third footballer can be born on any day, except d_1 and d_2:

d_3 \in \{1,2,3,\ldots 365\} \setminus \{d_1,d_2\}

so, the probability for the first three footballers to be born on three different days is

1 \cdot \dfrac{364}{365} \cdot \dfrac{363}{365}

And so on. With each new footballer we include, we have less and less options out of the 365 days, since more and more days will be already occupied by another footballer, and we can't have two players born on the same day.

The probability of all 22 footballers being born on 22 different days is thus

\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}

So, the probability that at least two footballers are born on the same day is

1-\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}

since the two events are complementary.

8 0
3 years ago
This property says you can rewrite 3x(4+5) as (3x4) + (3x5)
daser333 [38]
Distributive property
Step-by-step explanation:
Distributive property says that x(y + z) = (x*y) + (x *z)
6 0
2 years ago
What’s the answer to six plus negative 3
Alik [6]

6 + (-3) would be the same as just saying 6-3 which would be equal to positive 3

6 0
3 years ago
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